Question
Download Solution PDFA Merry-Go-Round is moving at а non-varying speed of 10 m/s. It implies that
This question was previously asked in
JTET 2012 (Mathematics & Science) Official Paper-II
Answer (Detailed Solution Below)
Option 2 : it is moving with uniform acceleration
Free Tests
View all Free tests >
CTET Paper 2 Maths & Science (ज्ञानसंगम): Mini Live Test
1 Users
60 Questions
60 Marks
60 Mins
Detailed Solution
Download Solution PDFThe correct answer is option 2 i.e. it is moving with uniform acceleration.
Concept:
- Uniform circular motion is where a moving object traces a circular path with constant speed.
- A circle is assumed to be a polygon with infinitely many sides such that each side approximates to a point.
- So, if the object moving on a circular path undergoes a change in direction at every point.
- Since direction changes and speed remains constant, velocity is varying at every point.
Explanation:
- The merry-go-round is under a uniform circular motion i.e. it has a constant magnitude of velocity, but the direction of velocity changes at every point.
- A change in velocity is due to a change in magnitude or direction or both.
- Acceleration occurs if there is a rate of change of velocity.
- Since it is moving with constant speed but the velocity changes, it is in uniform accelerated motion.
Last updated on Jun 18, 2025
-> The JTET 2024 Notiifcation has been cancelled by the authorities. The new notification will be released soon.
-> The Jharkhand TET is an eligibility test for the post of teacher (classes 1-8) in the schools of Jharkhand.
-> The written examination has two papers. Paper I is for the aspirants who wish to teach classes I to V class and Paper II is for aspirants who wish to teach classes VI to VIII
-> Candidates can refer to the JTET Exam Previous Year Papers to get an idea of the type of questions asked in the exam and prepare accordingly.