A bag contains only red, green and white balls. The probability of selecting a red ball from the bag at random is \(\frac{1}{3}\) and that of selecting a white ball at random is \(\frac{1}{2}\). If the bag contains 9 green balls, the total number of balls in the bag is:

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  1. 45
  2. 48
  3. 42
  4. 54

Answer (Detailed Solution Below)

Option 4 : 54
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Given:

Probability of red ball = 1/3

Probability of white ball = 1/2

Formula Used:

Probability = (Number of successful outcomes/Total number of outcomes)

P(E) = (nE)/(nS), where nE = Number of events and nS = Number of sample space 

Calculation:

Probability of getting green ball = 1 - (1/3 + 1/2)

⇒ 1 - 5/6 = 1/6

According to the question:

If one unit corresponds to 9 green balls then,

6 unit = 6 × 9 = 54

Total no. Of balls = 54

∴ The total number of balls in the bag is 54.

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