A 40 MVA, 11 KV, 3-phase, 50 Hz, 4-pole turbo alternator has an inertia constant of 15 sec. An input of 20 MW developed 15 MW of output power Then the acceleration is

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ESE Electrical 2018 Official Paper
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  1. 60°/s2
  2. 65°/s2
  3. 70°/s2
  4. 75°/s2

Answer (Detailed Solution Below)

Option 4 : 75°/s2
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ST 1: UPSC ESE (IES) Civil - Building Materials
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Detailed Solution

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VA rating (S) = 40 MVA

voltage (V) = 11 kV

Frequency (f) = 50 Hz

Number of poles (P) = 4

Inertia constant (H) = 15 sec

Input power (Pin) = 20 MW

output power (Pout) = 15 MW

Acceleration power Pa = Pin - Pout = 5 MW

\({P_a} = M\frac{{{d^2}\delta }}{{d{t^2}}} = M\alpha\)

\(\Rightarrow {P_a} = \left( {\frac{{SH}}{{180f}}} \right)\alpha\)

\(\Rightarrow \alpha = \frac{{5 \times {{10}^6} \times 180 \times 50}}{{40 \times {{10}^6} \times 15}}\)

= 75°/s2
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