Kinetics of Reaction MCQ Quiz in தமிழ் - Objective Question with Answer for Kinetics of Reaction - இலவச PDF ஐப் பதிவிறக்கவும்

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Latest Kinetics of Reaction MCQ Objective Questions

Top Kinetics of Reaction MCQ Objective Questions

Kinetics of Reaction Question 1:

Equal number of gas molecules A (mass 𝑚 and radius r) and B (mass 2m and radius 2r) are placed in two separate containers of equal volume. At a given temperature, the ratio of the collision frequency of B to that of A is

(Assume the gas molecules as hard spheres) 

  1. √2
  2. 2√2 1
  3. 1 ∶ √2
  4. ​1 ∶ 2√2

Answer (Detailed Solution Below)

Option 2 : 2√2 1

Kinetics of Reaction Question 1 Detailed Solution

CONCEPT:

Collision Frequency of Gas Molecules

  • The collision frequency Z of gas molecules is a measure of how frequently gas molecules collide with each other.
  • For gas molecules treated as hard spheres, the collision frequency is influenced by factors such as the number density, relative velocity, and the diameter of the molecules.
  • The collision frequency Z can be approximated using the formula:

    \( Z \propto \frac{1}{\text{molecular radius}} \cdot \sqrt{\frac{\text{Temperature}}{\text{molecular mass}}} \)

EXPLANATION:

We have two gases A and B:

Molecule A: mass = m, radius = r

Molecule B: mass = 2m, radius = 2r

Since both gases are at the same temperature, we can compare their collision frequencies based on their mass and radius.

The collision frequency ratio ZB : ZA is given by:

\( \frac{Z_B}{Z_A} = \frac{\left( \frac{1}{2r} \right) \sqrt{\frac{T}{2m}}}{\left( \frac{1}{r} \right) \sqrt{\frac{T}{m}}} \)

\(\frac{Z_B}{Z_A} = \frac{1}{2} \cdot \frac{1}{\sqrt{2}} = \frac{2}{\sqrt{2}} : 1 \)

Therefore, the ratio of the collision frequency of B to that of A is 2/√2 : 1.

Conclusion:

So, the correct option is 2.

Kinetics of Reaction Question 2:

The rate constant (kCT) of a bimolecular reaction according to collision theory is given by

\(k_{C T}=N_A\left(\frac{8 k_B T}{\pi \mu}\right)^{1 / 2} \sigma e^{-E_0 / R T}\)

E0 is related to activation energy (Ea) of the Arrhenius equation as

  1. \(E_0=\frac{R T}{2}+E_a\)
  2. \(E_a=R T+\frac{1}{2} E_0\)
  3. \(E_0=R T+\frac{1}{2} E_a\)
  4. \(E_a=\frac{R T}{2}+E_0\)

Answer (Detailed Solution Below)

Option 4 : \(E_a=\frac{R T}{2}+E_0\)

Kinetics of Reaction Question 2 Detailed Solution

CONCEPT:

Relationship Between \(E_0\) and \(E_a\) in Collision Theory

  • In collision theory, the rate constant \(k_{CT}\) for a bimolecular reaction is expressed as:
    • \(k_{CT} = N_A \left( \frac{8k_B T}{\pi \mu} \right)^{1/2} \sigma e^{-E_0}\)
  • Here, \(E_0\) is the threshold energy, the minimum energy that reactant molecules must have to initiate the reaction. This energy is directly linked to the activation energy \(E_a\) in the Arrhenius equation.
  • According to the Arrhenius equation:
    • \(k = A e^{-\frac{E_a}{RT}}\)
    •  

EXPLANATION:

  • The relation between the threshold energy \(E_0\) and the activation energy (\(E_a\)) is typically given by:
    • \(E_a = E_0 + mRT\)
  • Where:
    • \(E_a\) = activation energy
    • \(E_0\) = threshold energy
    • R = universal gas constant
    • T = temperature (in Kelvin)
    • m = constant, typically the power to which the temperature is raised (in this case,(\( m = \frac{1}{2})\)
  • Thus, for this specific reaction, the relation becomes:
    • \(E_a = E_0 + \frac{RT}{2}\)
  • Given the relation \(E_a = E_0 + \frac{RT}{2}\), we observe that the activation energy depends on both the threshold energy \(E_0\)and a temperature-dependent term \(\frac{RT}{2}\).
  • This equation indicates that as the temperature increases, the activation energy also increases due to the term \(\frac{RT}{2}\), making it easier for molecules to overcome the reaction barrier.
  • Based on this, the correct answer for the given question is:
    • \(E_a = \frac{RT}{2} + E_0\)

CONCLUSION:

  • The correct answer is: Option 4

Kinetics of Reaction Question 3:

Which of the following statements is not ture according to collision theory of reaction rates ?

  1. Collision of melecules is a precondition for any reaction to occur
  2. All collision result in the formation of the products
  3. Only activated collisions result in the fomation of the products
  4. Molecules which have acquired the energy of activation can collide effectively. 

Answer (Detailed Solution Below)

Option 2 : All collision result in the formation of the products

Kinetics of Reaction Question 3 Detailed Solution

Concept:

Collision Theory: This theory states that chemical reactions occur when reacting molecules or atoms collide with sufficient energy and proper orientation. The minimum energy required for a successful reaction upon collision is called the activation energy.

Explanation:

Statement 1: This is true. Collisions are indeed a precondition for any reaction to occur, as per collision theory.

Statement 2: This is incorrect. Not all collisions result in the formation of products. Only collisions with sufficient energy and proper orientation (activated collisions) result in a reaction.

Statement 3: This is true. Only activated collisions, meaning those with sufficient energy and correct orientation, result in the formation of products.

Statement 4: This is true. Molecules need to acquire the activation energy to collide effectively for a reaction to occur.

Conclusion:

The incorrect statement is: All collisions result in the formation of the products.

Kinetics of Reaction Question 4:

Which of the following statements are correct?

1. Order of a reaction can be known from experimental results and not from the stoichiometry of reaction.

2. Overall molecularity of a reaction may be determined in a manner similar to overall order of reaction.

3. Overall order of a reaction mA + nB  → P is m + n.

4. Molecularity a reaction refers to (i) each of the elementary steps in (an overall mechanism of) a complex reaction or (ii) a single step reaction.

Select the correct answer using the codes given below:

  1. 1, 2 and 3 
  2. 1, 3 and 4
  3. 1, 2 and 4 
  4. 2, 3 and 4.

Answer (Detailed Solution Below)

Option 3 : 1, 2 and 4 

Kinetics of Reaction Question 4 Detailed Solution

Concept:

Order of reaction: It refers to how the concentration of reactants affects the rate of a chemical reaction. It is determined experimentally and may be zero, first, second, or even higher order. Here’s a brief overview of each type:

  • Zero-order reaction: The rate of the reaction is independent of the concentration of the reactants. The rate law is typically expressed as: Rate=k

  • First-order reaction: The rate of the reaction is directly proportional to the concentration of one reactant. The rate law is typically expressed as: Rate=k[A], [A] is the concentration of the reactant and k is the rate constant.

  • Second-order reaction: The rate of the reaction is proportional to the square of the concentration of one reactant, or to the product of the concentrations of two reactants. The rate law can take forms like: Rate=k[A]2 or Rate=k[A][B]

Explanation:

Statement 1: Order of a reaction can be known from experimental results and not from the stoichiometry of reaction.

The order of a reaction is determined experimentally by studying how the rate changes with concentration of reactants. It cannot be inferred solely from the stoichiometry of the reaction.

This statement is correct.

Statement 2: Overall molecularity of a reaction may be determined in a manner similar to overall order of reaction.

Molecularity refers to the number of molecules coming together to react in a single step. While molecularity is typically an intrinsic property of each elementary step in the reaction mechanism, for complex reactions it might be conceptualized in a similar manner to overall reaction order—but it's not a directly analogous concept. 

This statement is correct.

Statement 3: Overall order of a reaction \(mA + nB \rightarrow P\ is\ m + n \).

Order of the reaction is determined experimentally not by using the stoichiometry of the reaction.

This statement is correct.

Statement 4: Molecularity of a reaction refers to (i) each of the elementary steps in (an overall mechanism of) a complex reaction or (ii) a single step reaction.

Molecularity is a concept that applies to elementary reactions and refers to the number of reactant molecules involved in an elementary step. For complex reactions, it refers to each individual step, while for a single step reaction, it refers to that single step.

This statement is correct.

Conclusion:

Statements 1, 2 and 4 are correct.

Kinetics of Reaction Question 5:

Consider the following statements

For the second order reaction, 2 A  → P roducts

1. The unit of the rate constant is concentration-1 time-1

2. t½ is directly proportional to the initial concentration

3. The plot of 1/concentration versus time would give a straight line.

Of these statements

  1. 1 and 3 are correct
  2. 1 and 2 are correct 
  3. 2 and 3 are correct
  4. 1, 2 and 3 are correct. 

Answer (Detailed Solution Below)

Option 1 : 1 and 3 are correct

Kinetics of Reaction Question 5 Detailed Solution

Concept:

Second-order reaction: The rate of the reaction is proportional to the square of the concentration of one reactant, or to the product of the concentrations of two reactants. The rate law can take forms like:
Rate=k[A]2, for 2A → Product

or Rate=k[A][B], for A+B → Product

Explanation:

Statement 1: The unit of the rate constant is concentration-1 time-1.

For a second-order reaction: Rate = k [A]2

Units of Rate : mol.L-1time-1

Units of k for second order: \({mole.L^{-1}.time^{-1}\over{(mole.L^{-1})^2}}= mole^{-1}Ltime^{-1}= concentration^{-1}time^{-1}\)

This statement is correct.

Statement 2: t½ is directly proportional to the initial concentration.

For second-order reactions: \(t_{1/2} = \frac1k [A]_0\)

This means t1/2 is inversely proportional to the initial concentration [A]0, not directly proportional. This statement is incorrect.

Statement 3: The plot of 1/concentration versus time would give a straight line.

For a second-order reaction:\( \frac{1}{[A]} = \frac{1}{[A]_{0}} + kt\)

This indicates that a plot of \({\frac{1}{[A]}}\ versus\ time (t)\) would yield a straight line. This statement is correct.

Conclusion:

Thus statement 1 and 3 are correct.

Kinetics of Reaction Question 6:

The decomposition of NH3 on platinum surface is zero order reaction. If k = 2.5 × 10-4 mol L-1s-1 the rate of production of H2 is

  1. 2.5 × 10-4 mol L-1s-1
  2. 7.5 × 10-4 mol L-1s-1
  3. 5.0 × 10-4 mol L-1s-1
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 2 : 7.5 × 10-4 mol L-1s-1

Kinetics of Reaction Question 6 Detailed Solution

\(2 \mathrm{NH}_3 \stackrel{\mathrm{Pt}}{\longrightarrow} \mathrm{N}_2+3 \mathrm{H}_2\)

As reaction is zero order

Rate = k[NH3]0

Rate = k

Rate = \(\frac{-1}{2} \frac{\Delta\left[\mathrm{NH}_3\right]}{\Delta \mathrm{t}}=\frac{1}{3} \frac{\Delta\left[\mathrm{H}_2\right]}{\Delta \mathrm{t}}=\mathrm{k}\)

\(\frac{\Delta H}{\Delta t}=3 k\)

= 3 × 2.5 × 10–4

= 7.5 × 10–4 mol L–1 s–1

Kinetics of Reaction Question 7:

The decomposition of NH3(g) on a hot Pt surface follows zero order kinetics at high pressure. What would be the rate constant for this reaction?

  1. s-1
  2. molL-1s-1
  3. molL-1s
  4. More than one of the above   
  5. None of the above

Answer (Detailed Solution Below)

Option 2 : molL-1s-1

Kinetics of Reaction Question 7 Detailed Solution

Correct answer: 2

Concept:

  • Zero-order reactions are those in which the rate of reaction does not change when the concentration of the reactants increases or decreases.
  • For a zero-order reaction, the rate law is given by,
  • rate = k[A]0, where k is the rate constant.
  • In the case of a zero-order reaction, the unit of rate constant k will be expressed in \({{{\rm{Concentration}}} \over {{\rm{Time}}}}\)

.

Explanation:

  • The reaction is a zero-order reaction.
  • The chemical reaction is given by,
  • 2NH3​→N2+3H2
  • Now for a zero-order reaction, the rate of the reaction is equal to the rate constant (Rate=k).
  • In a zero-order reaction, the rate constant is expressed as

                \({{{\rm{Concentration}}} \over {{\rm{Time}}}}\),

  • The unit of concentration is \({{{\rm{Mol}}} \over {{\rm{L}}}}\) ​, and 's' is a unit of second.
  • Thus the unit of k will be,\({\rm{k = }}{{{\rm{mol}}{\rm{/L}}} \over {\rm{s}}}\)
  •   \({\rm{ = mol}}{\rm{.}}{{\rm{L}}^{{\rm{ - 1}}}}{\rm{.}}{{\rm{s}}^{{\rm{ - 1}}}}\)

Conclusion:

Hence, the rate constant for a zero-order reaction is molL-1s-1.

Kinetics of Reaction Question 8:

The decomposition of NH3 on platinum surface is zero order reaction. If k = 2.5 × 10-4 mol L-1s-1 the rate of production of H2 is

  1. 2.5 × 10-4 mol L-1s-1
  2. 7.5 × 10-4 mol L-1s-1
  3. 5.0 × 10-4 mol L-1s-1
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 2 : 7.5 × 10-4 mol L-1s-1

Kinetics of Reaction Question 8 Detailed Solution

\(2 \mathrm{NH}_3 \stackrel{\mathrm{Pt}}{\longrightarrow} \mathrm{N}_2+3 \mathrm{H}_2\)

As reaction is zero order

Rate = k[NH3]0

Rate = k

Rate = \(\frac{-1}{2} \frac{\Delta\left[\mathrm{NH}_3\right]}{\Delta \mathrm{t}}=\frac{1}{3} \frac{\Delta\left[\mathrm{H}_2\right]}{\Delta \mathrm{t}}=\mathrm{k}\)

\(\frac{\Delta H}{\Delta t}=3 k\)

= 3 × 2.5 × 10–4

= 7.5 × 10–4 mol L–1 s–1

Kinetics of Reaction Question 9:

The molecularity of the following elementary reaction is NH4NO→ N2 + 2H2O

  1. Zero
  2. One
  3. Two
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 2 : One

Kinetics of Reaction Question 9 Detailed Solution

Explanation:

The molecularity of an elementary reaction is defined as the number of reactant particles that come together to form the products in a single step.

In the given reaction, NH4NO2 is directly decomposing into N2 and 2H2O. Therefore, this is an elementary reaction, and its molecularity can be determined by counting the number of molecules or atoms that are involved in the reaction.

As we can see, NH4NO2 is the only reactant molecule in this reaction, and it is breaking down into two product molecules, N2 and 2H2O. Therefore, the molecularity of this reaction is one.

The reaction can be represented as:

NH4NO2 → N2 + 2H2O

where NH4NO2 is the reactant and N2 and H2O are the products.

This reaction is an example of a unimolecular reaction, where only one molecule of the reactant is involved in the reaction. The decomposition of NH4NO2 is a first-order reaction, where the rate of the reaction is proportional to the concentration of NH4NO2.

The reaction can be further explained by looking at the balanced chemical equation:

NH4NO2 → N2 + 2H2O

1 molecule of NH4NO2 → 1 molecule of N2 + 2 molecules of H2O

In conclusion, the molecularity of the given elementary reaction NH4NO2 → N2 + 2H2O is one, which means it is a unimolecular reaction where one molecule of the reactant is involved in the reaction.

Only one reacting species is involved, therefore it is a unimolecular reaction.

Kinetics of Reaction Question 10:

The molecularity of the following elementary reaction is NH4NO→ N2 + 2H2O

  1. Zero
  2. One
  3. Two
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 2 : One

Kinetics of Reaction Question 10 Detailed Solution

Explanation:

The molecularity of an elementary reaction is defined as the number of reactant particles that come together to form the products in a single step.

In the given reaction, NH4NO2 is directly decomposing into N2 and 2H2O. Therefore, this is an elementary reaction, and its molecularity can be determined by counting the number of molecules or atoms that are involved in the reaction.

As we can see, NH4NO2 is the only reactant molecule in this reaction, and it is breaking down into two product molecules, N2 and 2H2O. Therefore, the molecularity of this reaction is one.

The reaction can be represented as:

NH4NO2 → N2 + 2H2O

where NH4NO2 is the reactant and N2 and H2O are the products.

This reaction is an example of a unimolecular reaction, where only one molecule of the reactant is involved in the reaction. The decomposition of NH4NO2 is a first-order reaction, where the rate of the reaction is proportional to the concentration of NH4NO2.

The reaction can be further explained by looking at the balanced chemical equation:

NH4NO2 → N2 + 2H2O

1 molecule of NH4NO2 → 1 molecule of N2 + 2 molecules of H2O

In conclusion, the molecularity of the given elementary reaction NH4NO2 → N2 + 2H2O is one, which means it is a unimolecular reaction where one molecule of the reactant is involved in the reaction.

Only one reacting species is involved, therefore it is a unimolecular reaction.

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