Tabulation and Line Graph MCQ Quiz - Objective Question with Answer for Tabulation and Line Graph - Download Free PDF

Solution:

Statement I:
Cost price of an article A = 1050

Selling price of an article A = 140/100 ×  1050 = Rs.1470

Marked price of an article A = 1470/80 ×  100 = Rs.1837.5

Marked price of an article A is non integer

Statement I is correct

Statement II: 

Difference between the cost price of article D and marked price of article E is not equal to cost price of any one of the given items.

Cost price of article D = 1800

Cost price of article E = 900

Selling price of article E = 900 ×  120/100 = 1080

Marked price of article E = 1080/40 ×  100 = 2700

Difference = 2700 - 1080 = 1620

None of the given item has not listed Rs. 1620 as the cost price

Statement II is wrong

III. Selling price of article C is divisible by 3,.

Cost price of article C = 1720 

Selling price of article C = 1720 ×  (160/100) = 2752

Statement III is wrong 

Solution:

Cost price of article C = 1720

Selling price of article C = 1720 ×  160/100 = 2752

Marked price of article C = 2752 /80 ×  100 = 3440

Marked price of article X = 3440 ×  125/100 = 4300

Required difference = (4300 - 3440) = 860

Solution:

Cost price of article B = 1600 

If it is marked 20% above its cost price = 1600 ×  120/100 = 1920

Cost price of article X = (1920 + 105)= √2025 = 45

Selling price of article X = (81 - 16) = 65

Profit percentage earned by selling article X = (65 - 45)/45 ×  100 = 44.44%

Solution:

Earlier profit percentage of article D = 50%

Profit of article D = 900 ×  (120/100) = Rs.1350

Profit amount earlier = 1350 - 900 = 450

Profit percentage of article now = 20%

Profit amount earned by article D now = 900 ×  20/100 = 180

Required difference = 450 - 180 = Rs. 270

Solution:

Cost price of article A = 1050

Cost price of article C = 1720

Profit percentage of article A = 40%

Profit percentage of article C = 60%

Selling price of article A = 1050 ×  (140/100) = Rs. 1470

Selling price of article C = 1720 ×  (160/100) = Rs. 2752

Required average = (1470 + 2752)/2 = Rs.2111

Calculation:

The ratio of number of car A and car B in 2012 = 17 : 16

The production of car A in 2012 = 850

Let the ratio of number of car A and car B be 17x and 16x respectively

⇒ 17x = 850

⇒ x = 50

The production of car B = 16x = 16 × 50 = 800

The number of car A manufactured in 2014 = 630

Required ratio = (800 : 630)

⇒ 80 : 63

∴  The ratio of number of Car B manufactured in 2012 to the number of Car A manufactured in 2014 is 80 : 63

Let the total number of employees in the the year 2005 be x

So, the total number of managers in 2005 = (80/100) × x = 0.8x

⇒ Total number of workers in 2005 = x – 0.8x = 0.2x

Hence, the number of male managers in 2005 = (5/8) × 0.8x = 0.5x

And the total number of employees in the the year 2006 be y

Also, So, the total number of managers in 2006 = (50/100) × y = 0.5y

⇒ Total number of workers in 2006 = y – 0.5y = 0.5y

Hence, the number of male managers in 2006 = (2/5) × 0.5y = 0.2y

As the number of workers is the same, we get:

0.2x = 0.5y

⇒ x = 2.5y      ----(i)

Using equation(i), the required ratio will become:

(0.5 × 2.5y)/0.2y = 25/4

∴ The reuqired ratio between the number of male managers in 2005 and 2006 is 25 ∶ 4

Formula used:

Percentage = (Part value/Original value) × 100

Calculation: 

Orders placed and delivered on Wednesday

⇒ 400 + 223 = 623

Orders placed and returned on Friday

⇒ 275 + 59.43

⇒ 334.43

Percentage

⇒ (623/334.43) × 100

⇒ 186.70% ≈ 186%

∴ The approximate percentage is 186%.

Given :

The students joined and left in different years 

Intial strength of school = 2000

Calculation :

Strength of school at the end of 2017 = 2000 + (375 - 250) + (350 - 425) + (400 - 220)

⇒ 2000 + 125 - 75 + 180 = 2230

∴ The answer is 2230.

Calculation:

Total items returned on Tuesday and Wednesday = (60.75 + 28.99) thousand = 89740

Average of items returned on Tuesday and Wednesday = 89740/2 = 44870

∴ 44870

Required average = Sum of observations/number of observations

Females in the month June = 250 × 50/100 = 125

Females in the month July = 200 × 20/100 = 40

The average of the female in the month of June and July by Driver A = (125 + 40)/2 = 82.5

Percentage of males in the month June = 100 - 70 = 30

Males in the month June = 350 × 30/100 = 105

Percentage of males in the month of July = 100 - 40 = 60

Males in the month July = 250 × 60/100 = 150

The average of the Males in the month of June and July by Driver B = (105 + 150)/2 = 127.5

 The ratio of the average of the female in the month of June and July by Driver A to the average of the males in the same month by Driver B

= 82.5 : 127.5 = 11 : 17

Let the number of employees in the company during each of the year be x

So, the number of managers in the year 2005 = (80/100)x = 0.8x

Among them, the number of male managers = (5/8) × 0.8x = 0.5x

Similarly,

So, the number of managers in the year 2006 = (50/100)x = 0.5x

Among them, the number of male managers = (2/5) × 0.5x = 0.2x

So, the percentage decrease in the number of male managers = [(0.5x – 0.2x)/0.5x] × 100 = 60%

Given: Number of delivered orders after cancellation of C = 15

Ratio of cancelled orders of C and E  = 5 : 6

Total number of cancelled orders for C = Total number of delivered orders for C 

Percentage of delivered orders of E = 80%

Calculation: 

Number of cancelled order of C = 15

Number of cancelled order of E = 15/5 × 6 = 18

Percentage of cancelled orders of E = 20%

Total number of orders of E = 18/20 × 100 = 90

Calculations:

From the line graph given, we can get the total population of villages (M, N, O, P, Q ,and R).

From the table provided, We can find 4 parameters only:

1. Literate people of a particular village (Ratio of literate to illiterate)

2. Illiterate people of a particular village (Ratio of literate to illiterate)

3. Male population of a particular village (Percentage of male population)

4. Female population of a particular village (Percentage of male population)

All Data that can be derived from the Line graph and Tabulation is summarised below.

As we can see from the data we can't infer number of literate males.

Hence, The ratio can't be determined  

Individual Solution:

We can not find ratio of literate and illiterate male From M,N and O.

⇒ Male from village P, Q and R = 2000 + 2200 + 1800 = 6000

∴ The ratio can't be determined