Clock and Calendar MCQ Quiz - Objective Question with Answer for Clock and Calendar - Download Free PDF

Last updated on May 28, 2025

Calendars and clocks are included in aptitude. Here, the clock serves as a tool for displaying the passage of time, while the calendar helps us determine the current month, day, and year. Competitive exams like as those for the SSC, RRB, Railway, and Teaching jobs frequently include questions based on time and the calendar. When solving problems involving clocks and calendars, it is important to have a firm understanding of some fundamental concepts. These include the differences between the shapes of the clock hands, their angles with respect to the hours, days, and months, as well as leap years and other calendar elements. Focus more on daily practise, tips, and techniques. Some websites also offer exam series relevant to this subject. The best illustration of this is Testbook.

Latest Clock and Calendar MCQ Objective Questions

Clock and Calendar Question 1:

If today is Tuesday, which day was three days ago?

  1. Saturday
  2. Friday
  3. Wednesday
  4. Thursday

Answer (Detailed Solution Below)

Option 1 : Saturday

Clock and Calendar Question 1 Detailed Solution

Given: Today is Tuesday.

We need to find out which day was three days ago.

Counting backward from Tuesday:

  • One day ago was Monday.
  • Two days ago was Sunday.
  • Three days ago was Saturday.

Therefore, three days ago was Saturday.

Hence, the correct answer is "Option 1".

Clock and Calendar Question 2:

If 13 September 2003 is a Saturday, then what will be the day of the week on 14 February 2005?

  1. Friday
  2. Wednesday
  3. Monday
  4. Saturday
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : Monday

Clock and Calendar Question 2 Detailed Solution

Given : 13 September 2003 is a Saturday

  • Total number of days in a normal year = 365
  • Total number of days in a leap year = 366
  • Total number of odd days in a normal year = 365/7 = 1 
  • Total number of odd days in a leap year = 366/7 = 2
  • 13 September 2003 (Saturday) + 2 odd days = 13 September 2004 (Monday)
  • Total number of days from 13 September 2004 to 14 February 2005 = 17 (September) + 31 (October) + 30 (November) + 31 (December) + 31 (January) + 14 (February) = 154
  • Total number of odd days from 13 September 2004 to 14 February 2005 = 154/7 = 0
  • Starting from 13 September 2004, every 7th day will be Monday.
  • Since there is no odd day between 13 September 2004 and 14 February 2005, so 14 February 2005 will be held on Monday.

Hence, 'option 3' is the correct answer.

Clock and Calendar Question 3:

The Calendar of the year 2009 is same as that of the year

  1. 2013
  2. 2014
  3. 2015
  4. 2016

Answer (Detailed Solution Below)

Option 3 : 2015

Clock and Calendar Question 3 Detailed Solution

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A calendar year is repeated every 7 odd days.

No. of odd days in non leap year = Remainder of (365 ÷ 7) = 1 odd day

No. of odd days in leap year = Remainder of (366 ÷ 7) = 2 odd days

Now, 7 odd days will come in 6 years (5 non leap years and 1 leap year).

Thus, year with same calendar as 2009 will be 2009 + 6 = 2015.

Hence, the correct answer "Option 3".

Clock and Calendar Question 4:

If the 6th day of a month is 2 days earlier than Thursday. What day will it be on the 18th day of the month ?

  1. Tuesday
  2. Wednesday
  3. Sunday
  4. monday

Answer (Detailed Solution Below)

Option 3 : Sunday

Clock and Calendar Question 4 Detailed Solution

Given: 6th day of a month is 2 days earlier than Thursday.

So, (6th day + 2 days) 6th day of the month is → Thursday - 2 → Tuesday

According to the question, 18th day of the month will be:

Odd no of days = (18 - 6) ÷ 7 → 5 odd days

18th day of the month = Tuesday + 5 → Sunday

Hence, "Option 3" is the correct answer.

Clock and Calendar Question 5:

At what angle the hands of a clock are inclined at 50 minutes past 4 ?

  1. 125
  2. 150
  3. 155
  4. 160

Answer (Detailed Solution Below)

Option 3 : 155

Clock and Calendar Question 5 Detailed Solution

Given time: 50 minutes past 4 → 4 : 50

Angle traced = 11/2 × Number of Minutes - 30 × Number of Hours

Angle traced = 11/2 × 50 - 30 × 4

Angle traced = 155°

Hence, "Option 3" is the correct answer.

Additional Information
 
Movement of Hour head

12 hr = 360º

1 hr = 30º

60 min = 30º

1 min = 0.5º

Movement of Minute head       

1 hr =  360º

60 min = 360º

1 min = 6º   

5 min = 30º     

Movement of Seconds head       

1 min =  360º

60 sec = 360º

1 sec = 6º   

5 sec = 30º

Gapping between hour head and minute head

​55 min = 60 min       

1 min = 60/55 

Top Clock and Calendar MCQ Objective Questions

Which of the following calendars will be the same as the calendar for the year 2003?

  1. 2014
  2. 2013
  3. 2012
  4. 2011

Answer (Detailed Solution Below)

Option 1 : 2014

Clock and Calendar Question 6 Detailed Solution

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Given : Year 2003 = (Leap year + 3)  = 2000 + 3

Explanation : 

In case of a repeating year, we add (11) to the given year :

So, 

2003 + 11 ⇒ 2014

Hence, "2014" is the correct answer.

Additional Information 

  •  Trick to remember:
Years Repetition after years
Leap year 28
(Leap year + 1) or ordinary year 6
(Leap year + 2) or ordinary year 11
(Leap year + 3) or ordinary year 11

On 8th February, 2020 it was Saturday. What was the day of the week on 1st February, 2016 ?

  1. Sunday 
  2. Monday
  3. Tuesday
  4. Wednesday

Answer (Detailed Solution Below)

Option 2 : Monday

Clock and Calendar Question 7 Detailed Solution

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Odd days:
A leap year has 366 days and a non-leap year has 365 days.

Leap year = 366 days or 52 weeks and 2 days. So, here the number of odd days are 2.

Non - Leap year = 365 days or 52 weeks and 1 day. So, here the number of odd days is 1.

Number of odd days in the following years

2017

2018

2019

2016

1

1

1

2


Total number of odd days in all the years combined = 1+1+1+2 = 5

Code of the day

Day

0

Sunday

1

Monday

2

Tuesday

3

Wednesday

4

Thursday

5

Friday

6

Saturday


 8th February 2020  was Saturday

Code for Saturday is 6 and the number of odd days in all the years combined is 5. So, 6 - 5 = 1

1 is the code for Monday.

Hence, 1st February 2016 was Monday.

What day of the week will be on 1st January 2033?

  1. Saturday
  2. Monday
  3. Sunday
  4. Tuesday

Answer (Detailed Solution Below)

Option 1 : Saturday

Clock and Calendar Question 8 Detailed Solution

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Given : Year - 2033

Explanation:

Calculating the odd days for 31st December 2032 :

2032 can be written as → (2000 + 32) so,

2000 → 0

And,

32 → Dividing 32 by 4 will give get quotient 8 i.e:

qImage12076 

Now, 40 ÷ 7 = Remainder = 5

As 5 is the code for Friday , thus it is Friday on 31st December 2032.

And, 

1st January is one day after 31st December 2032, so it will be Saturday.

Hence, "Saturday" is the correct answer.

 Additional Information

  1. Ordinary year (365 days) = 1 odd day
  2. Leap year (366 days) = 2 odd days

 

  • Number of odd days for the days of week.
Days Odd days
Sunday 0
Monday 1
Tuesday 2
Wednesday 3
Thursday 4
Friday 5
Saturday 6

 

  • Number of odd days for the days of months.
Months having  number of days Odd days
28 days 0
29 days 1
30 days 2
31 days 3

 

  • Number of odd days for the years.
Years Odd days
100 5
200 3
300 1
400 0

Note - Any multiple year of 400 like 800, 1200,1600, 2000 etc will have '0' Odd days.

If 11th August 2004 is on Friday then what will be the day of 11th February 2006?

  1. Sunday
  2. Friday
  3. Monday
  4. Wednesday

Answer (Detailed Solution Below)

Option 3 : Monday

Clock and Calendar Question 9 Detailed Solution

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Given: 11th August 2004 = Friday.

Now,

Total days between 11th August 2004 to 11th February 2006

= 20(Aug) + 30(Sept) + 31(Oct) + 30(Nov) + 31(Dec) + 365(2005) + 31(Jan) + 11(Feb) = 549 days.

And, 549/7 = 78 week and 3 odd days.

So, 11th February 2006 = Friday + 3 = Monday.

Hence, the correct answer is "Monday".

A clock is fixed on a horizontal table. At 3 pm its minute hand is pointing towards North. At 3.40 pm, the minute hand will point towards?

  1. 60° south of west
  2. South-east
  3. 60° west of south
  4. South-west

Answer (Detailed Solution Below)

Option 3 : 60° west of south

Clock and Calendar Question 10 Detailed Solution

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Given, at 3 pm

F2 Madhuri Railways 11.07.2022 D1

Now at 3.40 pm

F2 Madhuri Railways 11.07.2022 D2

In every 5 minutes movement minute hand will make an angle of 30°, thus between 3.30 pm and 3.40 pm it will make an angle of 60° (5 min. + 5 min. = 30° + 30° )

Therefore minute hand is pointing 60° west (9) of the south (6).

Hence, “60° west of south” is the correct answer.

What is the day on 8th March 2017?

  1. Monday
  2. Wednesday
  3. Friday
  4. Sunday

Answer (Detailed Solution Below)

Option 2 : Wednesday

Clock and Calendar Question 11 Detailed Solution

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Consider, 

Monday= 1

Tuesday = 2

Wednsday = 3

Thursday = 4

Friday = 5 

Saturday = 6

Sunday = 7

As 2000 is divisible by 400 the number of odd days is 0.

Number of leap years till 2016 = 4 (2004, 2008, 2012 and 2016)

Number of ordinary years till 2016 = 12

Number of odd days till 2016 = 12 + (4 × 2) = 20 odd days

Number of odd days in January, 2017 = 3

Number of odd days in February, 2017 = 0

Total number of odd days till 8th March 2017 = 20 + 3 + 8 = 31 odd days = 3 odd days

So, the day on 8th March 2017 is Wednesday.

If 14 January 2022 was Friday, then what will be the day of the week on 28 February 2025?

  1. Friday
  2. Monday
  3. Sunday
  4. Saturday

Answer (Detailed Solution Below)

Option 1 : Friday

Clock and Calendar Question 12 Detailed Solution

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The correct answer is option(1)

In any two consecutive ordinary years, date of the next year will be one day ahead of the same date of the previous year.

14 January 2022 = Friday

14 January 2023 = Saturday

14 January 2024 = Sunday

If an ordinary year comes immediately after a leap year, then the day on a certain date of the ordinary year will be 2 days ahead of the same date of the leap year upto February

14 January 2025 = Tuesday

From 14 January 2025 to 28 February 2025 = 45 days (42 + 3)

Number of odd days = 3 days

Therefore, 28 February = Friday (3 days ahead from Tuesday)

Hence, the correct answer is Option(1)

If 19 July 2000 was a Wednesday, then what would be the day of the week on 15 June 2012?

  1. Saturday
  2. Friday
  3. Thursday
  4. Wednesday

Answer (Detailed Solution Below)

Option 2 : Friday

Clock and Calendar Question 13 Detailed Solution

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Odd days:

A non-leap year has 365 days and a leap year has 366 days.

Non-leap year = 365 days or 52 weeks and 1 day. So, here the number of odd days is 1.

Leap year = 366 days or 52 weeks and 2 days So, here the number of odd days are 2.

Leap year between 2000 to 2012 = 2004, 2008 and 2012

And,

The non-leap year between 2000 and 2012 = 2001, 2002, 2003, 2005, 2006, 2007, 2009, 2010 and 2011

So, total number of odd day between 2000 and 2012 = 9 (Total Non- leap year) + 2 + 2 + 2 = 15 days = 1 odd day

Code of the day

Day

0

Sunday

1

Monday

2

Tuesday

3

Wednesday

4

Thursday

5

Friday

6

Saturday

 

19 July 2000 was a Wednesday

=> Day on 19 July 2012 = Wednesday + 15

= Wednesday + remainder of 15/7

= Wednesday + 1 (odd day) = Thursday

Therefore, 19 July 2012 = Thursday

Now,

15 June 2012 = 19 July 2012 – 34 days

= Thursday – 34

= Thursday – the remainder of 34/7

= Thursday – 6 (In reverse direction)

= Friday

Hence, 15 June 2012 was “Friday”.

At 3:30 p.m., the minute hand of a clock points towards East. Towards which direction the hour hand will point at 9:00 p.m.?

  1. South
  2. East
  3. South-West
  4. None of these

Answer (Detailed Solution Below)

Option 1 : South

Clock and Calendar Question 14 Detailed Solution

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At 3:30 p.m., the minute hand of a clock points towards East.

6151b735241c7f01f2c33684 16425896105841

similarly,

The hour hand at 9:00 p.m. will point towards South.

F1 Puja Madhuri 27.10.2021 D2 Corr

Hence, 'South' is the correct answer.

Which of the following calendars will be the same as the calendar for the year 2009?

  1. 2025
  2. 2015
  3. 2036
  4. 2042

Answer (Detailed Solution Below)

Option 2 : 2015

Clock and Calendar Question 15 Detailed Solution

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The pattern followed here is:

The total number of odd days is listed below:

Year Odd days
2009 1
2010 1
2011 1
2012 2
2013 1
2014 1

Total odd days

7

Therefore 2015 will be the repeated calendar of 2009.Shortcut Trick

Year Repetition after years
Leap year 28
Leap year + 1 6
Leap year + 2 11
Leap year + 3 11

So, 2008 + 1 = 2009 + 6 = 2015

So, 2015 is the same as the calendar for the year 2009

Hence, the correct answer is "2015".

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