Clock and Calendar MCQ Quiz - Objective Question with Answer for Clock and Calendar - Download Free PDF
Last updated on Jun 23, 2025
Latest Clock and Calendar MCQ Objective Questions
Clock and Calendar Question 1:
If 9 March 2007 was Friday, then what was the day of the week on 13 March 2012?
Answer (Detailed Solution Below)
Clock and Calendar Question 1 Detailed Solution
Given: 9 March 2007 was Friday.
Now,
2007 to 2012 = 5 Years (3 Ordinary Years and 2 Leap Year 2008, 2012).
So, 2 Leap Year has 4 odd days,
And, 3 Ordinary Years have 3 odd days.
Total odd days = 4 + 3 = 7 odd days.
→ 7 odd days = 7/7 = 1 week and 0 odd day.
Then, 9 March 2012 will be Friday + 0 = Friday.
Now, the number of days between 9 March 2012 to 13 March 2012
= 4 days.
So, 13 March 2012 will be Friday + 4 = Tuesday.
Hence, the correct answer is "Option 3".
Clock and Calendar Question 2:
After 36 days it will be a Sunday. What day is it today?
Answer (Detailed Solution Below)
Clock and Calendar Question 2 Detailed Solution
Given: After 36 days it will be a Sunday.
Now,
The number of days in a week = 7.
So, 36 days → 36/7 = 5 weeks and 1 odd day.
Thus, 36 days from today will be 5 weeks and 1 day ahead of today.
Since 36 days from today is a Sunday,
1 day before Sunday is Saturday.
Hence, the correct answer is "Option 1".
Clock and Calendar Question 3:
If International Women's day was on Tuesday in 2013, what day will it be in 2014?
Answer (Detailed Solution Below)
Clock and Calendar Question 3 Detailed Solution
The logic follows here is:
As we observe International Woman's Day on 8th March.
Given,
International Women's day was on Tuesday in 2013 means 8th March was Tuesday.
Now, we have to calculate the odd days from 8th March 2013 to 8th March 2014.
8th March 2013 to 8th March 2014 = 365 days
When 365 is divided by 7,
The remainder is 1.
= 1 odd day i.e. 1 more day after Tuesday.
Therefore, International Women's day in 2014 will fall on Wednesday.
Hence, the correct answer is "Wednesday".
Additional Information
Year - One year has 365 days or 366 days on this basis the year is divided into two parts:
- Normal year - It has 365 days.
- Leap year - It has 366 days and completely divisible by 4.
Century leap year - The year which is exactly divisible by 400. Example - 1200, 1600, 2000 etc.
Counting of Odd days
Ordinary Year : 365 days ( 52 weeks + 1 days)
= 1 Odd days
Leap Year : 366 days ( 52 weeks + 2 days)
= 2 Odd days
In an ordinary year, there are 365 days and on dividing 365 by 7,
we get remainder = 1 so this extra one day is taken as an odd day.
Similarly, in a leap year, there are 366 days and on dividing 366 by 7,
we get remainder = 2 so these extra days are taken as the odd days.
Thus, the remainder, which we get after dividing the number of days by 7 is considered as odd days.
Clock and Calendar Question 4:
If 1st October falls on Monday, which day will fall three days after the 20th of that month?
Answer (Detailed Solution Below)
Clock and Calendar Question 4 Detailed Solution
Given That 1st October is Monday.
1st October | 8th October | 15th October | 22nd October |
Monday | Monday | Monday | Monday |
So 22nd October is Monday, we have to find three day after 20th October that is 23 October:
22nd October = Monday
23rd October = Tuesday
Hence "Tuesday" is Correct answer
Clock and Calendar Question 5:
The calendar for the year 2077 will be the same for the year:
Answer (Detailed Solution Below)
Clock and Calendar Question 5 Detailed Solution
The logic follows here is :
- A leap year repetition will be a on a leap year.
- A non-leap year repetition will be a on a non-leap year.
- A calendar year is repeated after every 7 odd days.
- No. of odd days in non-leap year = Remainder of (365 ÷ 7) = 1 odd days.
- No. of odd days in leap year = Remainder of (366 ÷ 7) = 2 odd days.
Calculate the year gap with a multiple of 7.
If the leap year repetition comes after 7 odd days is also a leap year then it will be the answer, otherwise count for next multiple of 7. Same for the non-leap year also.
Explanation:
Here, the given year is 2077. It is a non-leap year, so we will count odd days from it :
2077 → 1 odd day
2078 → 1 odd day
2079 → 1 odd day
2080 → 2 odd days
2081 → 1 odd day
2082 → 1 odd day
Total = 7 odd days
Thus, 2077 will be repeated after 7 odd days i.e. in 2083.
Hence, the correct answer is "2083".
Shortcut Trick
Year | Repetition after years |
Leap year | 28 |
Leap year + 1 | 6 |
Leap year + 2 | 11 |
Leap year + 3 | 11 |
Here, 2077 is a (leap year + 1) year, therefore it will repeat after 6 years i.e. in 2083.
Top Clock and Calendar MCQ Objective Questions
Which of the following calendars will be the same as the calendar for the year 2003?
Answer (Detailed Solution Below)
Clock and Calendar Question 6 Detailed Solution
Download Solution PDFGiven : Year 2003 = (Leap year + 3) = 2000 + 3
Explanation :
In case of a repeating year, we add (11) to the given year :
So,
2003 + 11 ⇒ 2014
Hence, "2014" is the correct answer.
Additional Information
- Trick to remember:
Years | Repetition after years |
Leap year | 28 |
(Leap year + 1) or ordinary year | 6 |
(Leap year + 2) or ordinary year | 11 |
(Leap year + 3) or ordinary year | 11 |
On 8th February, 2020 it was Saturday. What was the day of the week on 1st February, 2016 ?
Answer (Detailed Solution Below)
Clock and Calendar Question 7 Detailed Solution
Download Solution PDFOdd days:
A leap year has 366 days and a non-leap year has 365 days.
Leap year = 366 days or 52 weeks and 2 days. So, here the number of odd days are 2.
Non - Leap year = 365 days or 52 weeks and 1 day. So, here the number of odd days is 1.
Number of odd days in the following years
2017 |
2018 |
2019 |
2016 |
1 |
1 |
1 |
2 |
Total number of odd days in all the years combined = 1+1+1+2 = 5
Code of the day |
Day |
0 |
Sunday |
1 |
Monday |
2 |
Tuesday |
3 |
Wednesday |
4 |
Thursday |
5 |
Friday |
6 |
Saturday |
8th February 2020 was Saturday
Code for Saturday is 6 and the number of odd days in all the years combined is 5. So, 6 - 5 = 1
1 is the code for Monday.
Hence, 1st February 2016 was Monday.
What day of the week will be on 1st January 2033?
Answer (Detailed Solution Below)
Clock and Calendar Question 8 Detailed Solution
Download Solution PDFGiven : Year - 2033
Explanation:
Calculating the odd days for 31st December 2032 :
2032 can be written as → (2000 + 32) so,
2000 → 0
And,
32 → Dividing 32 by 4 will give get quotient 8 i.e:
Now, 40 ÷ 7 = Remainder = 5
As 5 is the code for Friday , thus it is Friday on 31st December 2032.
And,
1st January is one day after 31st December 2032, so it will be Saturday.
Hence, "Saturday" is the correct answer.
Additional Information
- Ordinary year (365 days) = 1 odd day
- Leap year (366 days) = 2 odd days
- Number of odd days for the days of week.
Days | Odd days |
Sunday | 0 |
Monday | 1 |
Tuesday | 2 |
Wednesday | 3 |
Thursday | 4 |
Friday | 5 |
Saturday | 6 |
- Number of odd days for the days of months.
Months having number of days | Odd days |
28 days | 0 |
29 days | 1 |
30 days | 2 |
31 days | 3 |
- Number of odd days for the years.
Years | Odd days |
100 | 5 |
200 | 3 |
300 | 1 |
400 | 0 |
Note - Any multiple year of 400 like 800, 1200,1600, 2000 etc will have '0' Odd days.
If 11th August 2004 is on Friday then what will be the day of 11th February 2006?
Answer (Detailed Solution Below)
Clock and Calendar Question 9 Detailed Solution
Download Solution PDFGiven: 11th August 2004 = Friday.
Now,
Total days between 11th August 2004 to 11th February 2006
= 20(Aug) + 30(Sept) + 31(Oct) + 30(Nov) + 31(Dec) + 365(2005) + 31(Jan) + 11(Feb) = 549 days.
And, 549/7 = 78 week and 3 odd days.
So, 11th February 2006 = Friday + 3 = Monday.
Hence, the correct answer is "Monday".
If 14 January 2022 was Friday, then what will be the day of the week on 28 February 2025?
Answer (Detailed Solution Below)
Clock and Calendar Question 10 Detailed Solution
Download Solution PDFThe correct answer is option(1)
In any two consecutive ordinary years, date of the next year will be one day ahead of the same date of the previous year.
14 January 2022 = Friday
14 January 2023 = Saturday
14 January 2024 = Sunday
If an ordinary year comes immediately after a leap year, then the day on a certain date of the ordinary year will be 2 days ahead of the same date of the leap year upto February
14 January 2025 = Tuesday
From 14 January 2025 to 28 February 2025 = 45 days (42 + 3)
Number of odd days = 3 days
Therefore, 28 February = Friday (3 days ahead from Tuesday)
Hence, the correct answer is Option(1)
A clock is fixed on a horizontal table. At 3 pm its minute hand is pointing towards North. At 3.40 pm, the minute hand will point towards?
Answer (Detailed Solution Below)
Clock and Calendar Question 11 Detailed Solution
Download Solution PDFGiven, at 3 pm
Now at 3.40 pm
In every 5 minutes movement minute hand will make an angle of 30°, thus between 3.30 pm and 3.40 pm it will make an angle of 60° (5 min. + 5 min. = 30° + 30° )
Therefore minute hand is pointing 60° west (9) of the south (6).
Hence, “60° west of south” is the correct answer.What is the day on 8th March 2017?
Answer (Detailed Solution Below)
Clock and Calendar Question 12 Detailed Solution
Download Solution PDFConsider,
Monday= 1
Tuesday = 2
Wednsday = 3
Thursday = 4
Friday = 5
Saturday = 6
Sunday = 7
As 2000 is divisible by 400 the number of odd days is 0.
Number of leap years till 2016 = 4 (2004, 2008, 2012 and 2016)
Number of ordinary years till 2016 = 12
Number of odd days till 2016 = 12 + (4 × 2) = 20 odd days
Number of odd days in January, 2017 = 3
Number of odd days in February, 2017 = 0
Total number of odd days till 8th March 2017 = 20 + 3 + 8 = 31 odd days = 3 odd days
So, the day on 8th March 2017 is Wednesday.If 19 July 2000 was a Wednesday, then what would be the day of the week on 15 June 2012?
Answer (Detailed Solution Below)
Clock and Calendar Question 13 Detailed Solution
Download Solution PDFOdd days:
A non-leap year has 365 days and a leap year has 366 days.
Non-leap year = 365 days or 52 weeks and 1 day. So, here the number of odd days is 1.
Leap year = 366 days or 52 weeks and 2 days So, here the number of odd days are 2.
Leap year between 2000 to 2012 = 2004, 2008 and 2012
And,
The non-leap year between 2000 and 2012 = 2001, 2002, 2003, 2005, 2006, 2007, 2009, 2010 and 2011
So, total number of odd day between 2000 and 2012 = 9 (Total Non- leap year) + 2 + 2 + 2 = 15 days = 1 odd day
Code of the day |
Day |
0 |
Sunday |
1 |
Monday |
2 |
Tuesday |
3 |
Wednesday |
4 |
Thursday |
5 |
Friday |
6 |
Saturday |
19 July 2000 was a Wednesday
=> Day on 19 July 2012 = Wednesday + 15
= Wednesday + remainder of 15/7
= Wednesday + 1 (odd day) = Thursday
Therefore, 19 July 2012 = Thursday
Now,
15 June 2012 = 19 July 2012 – 34 days
= Thursday – 34
= Thursday – the remainder of 34/7
= Thursday – 6 (In reverse direction)
= Friday
Hence, 15 June 2012 was “Friday”.
At 3:30 p.m., the minute hand of a clock points towards East. Towards which direction the hour hand will point at 9:00 p.m.?
Answer (Detailed Solution Below)
Clock and Calendar Question 14 Detailed Solution
Download Solution PDFAt 3:30 p.m., the minute hand of a clock points towards East.
similarly,
The hour hand at 9:00 p.m. will point towards South.
Hence, 'South' is the correct answer.
Which of the following calendars will be the same as the calendar for the year 2009?
Answer (Detailed Solution Below)
Clock and Calendar Question 15 Detailed Solution
Download Solution PDFThe pattern followed here is:
The total number of odd days is listed below:
Year | Odd days |
2009 | 1 |
2010 | 1 |
2011 | 1 |
2012 | 2 |
2013 | 1 |
2014 | 1 |
Total odd days |
7 |
Therefore 2015 will be the repeated calendar of 2009.Shortcut Trick
Year | Repetition after years |
Leap year | 28 |
Leap year + 1 | 6 |
Leap year + 2 | 11 |
Leap year + 3 | 11 |
So, 2008 + 1 = 2009 + 6 = 2015
So, 2015 is the same as the calendar for the year 2009
Hence, the correct answer is "2015".