Question
Download Solution PDFComprehension
Consider the following for the two (02) items that follow:
\(\text{Let } f(x)= \begin{cases} x^3, & x^2 < 1 \\ x^2, & x^2 \ge 1 \end{cases} \\\)
What is \(\lim_{x \to 0} f'(x)\) equal to?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Given,
The function is defined as:
\( f(x) = \begin{cases} x^3, & \text{if} \, |x| < 1 \\ x^2, & \text{if} \, |x| \geq 1 \end{cases} \)
We are tasked with finding:
\( \lim_{x \to 0} f'(x) \)
For |x| < 1 , the function is f(x) = x3, so the derivative is:
\( f'(x) = 3x^2 \)
Now, compute the limit of the derivative as x to 0:
\( \lim_{x \to 0} f'(x) = \lim_{x \to 0} 3x^2 = 0 \)
∴ The value of \(\lim_{x \to 0} f'(x) \)is 0.
The correct answer is Option (c)
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