Question
Download Solution PDFWhat is \(\frac{1}{{{{\log }_2}N}} + \frac{1}{{{{\log }_3}N}} + \frac{1}{{{{\log }_4}N}} + \ldots + \frac{1}{{{{\log }_{100}}N\;}}\;\) equal to (N ≠ 1)?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Formula used:
- \({\log _a}b = \frac{1}{{{{\log }_b}a}}\)
- Loga M + loga N = loga (MN)
Factorial:
- n! = 1 × 2 × 3 × ⋯ × (n – 1) × n
Calculation:
Using \({\log _a}b = \frac{1}{{{{\log }_b}a}}\)
\(\frac{1}{{{{\log }_2}{\rm{N}}}} + \frac{1}{{{{\log }_3}{\rm{N}}}} + \ldots + \frac{1}{{{{\log }_{100}}{\rm{N\;}}}} = {\log _{\rm{N}}}2 + {\log _{\rm{N}}}3 + \ldots + {\log _{\rm{N}}}100\)
= logN (2 × 3 × ⋯ × 100)
= logN (100!)
\(= \frac{1}{{{{\log }_{100!}}N}}\)
Last updated on Jun 18, 2025
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