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Two solid rubber balls A and B having masses 200 & 400 gm respectively are moving in opposite direction with velocity of A equal to 0.3 m/sec. After collision the two balls come to rest when the velocity of B is

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AIIMS BSc NURSING 2024 Memory-Based Paper
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  1. 0.15 m/sec
  2. 1.5 m/sec
  3. -0.15 m/sec
  4. None of these

Answer (Detailed Solution Below)

Option 3 : -0.15 m/sec
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Detailed Solution

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Calcultion:
Initial momentum of Ball A = 0.2 × 0.3 = 0.06 kg·m/s

Initial momentum of Ball B = 0.4 × vB

Total initial momentum = 0.06 + 0.4 × vB

According to conservation of momentum:

0.06 + 0.4 × vB = 0

0.4 × vB = -0.06

vB = -0.06 / 0.4

vB = -0.15 m/sec

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-> The AIIMS BSc Nursing (Hons) Result 2025 has been announced.

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-> AIIMS BSc Nursing Notification 2025 was released for admission to the 2025 academic session.

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