Answer (Detailed Solution Below)

Option 2 : 1
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Detailed Solution

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Concept:

-1 ≤ sin θ ≤ 1

0 ≤ sin2 θ ≤ 1

sin 2 θ = 2 sin θ cos θ

Calculation

We have to find the maximum value of 1 − 4 sin2 x cos2 x

Let f(x) = 1 − 4 sin2 x cos2 x

= 1 – (2 sin x cos x)2

= 1 – sin2 2x                   (∵sin 2θ = 2 sin θ cos θ)

For maximum value of f(x), sin 2x should be minimum

As we know that,

Minimum value of sin2 θ is 0

Therefore, Maximum value of f(x) = 1 – 0 = 1

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