The maximum net specific work obtainable in an ideal Brayton cycle for Tmax = 900 K and

min = 400 K is given by

This question was previously asked in
ESE Mechanical 2015 Paper 1: Official Paper
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  1. 100 Cp
  2. 500 Cp
  3. 700 Cp
  4. 800 Cp

Answer (Detailed Solution Below)

Option 1 : 100 Cp
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Detailed Solution

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Concept:

A gas turbine works upon the Brayton cycle.

F1 M.J Madhu 09.04 20 D2F1 M.J Madhu 09.04 20 D1

In order to achieve maximum work, the temperature after compression (T2) and after exhaust from the turbine (T4) is given by

\({{\rm{T}}_2} = {{\rm{T}}_4} = {\rm{\;}}\sqrt {{{\rm{T}}_{{\rm{max}}}} \times {\rm{\;}}{{\rm{T}}_{{\rm{min}}}}} = \sqrt {{{\rm{T}}_3} \times {\rm{\;}}{{\rm{T}}_1}}\)

Where T3 is the temperature at the turbine inlet and T1 is the temperature of the air before compression

Since compressor also consumes the work, therefore, the net work is the difference between the work done by the turbine and the work consumed by the compressor

Maximum net specific work obtainable = Turbine work – Compressor work

Wnet = wT - wC

wT = Cp (T3 – T4)

WC = Cp (T2 – T1)

Calculation:

Given, Tmax = 900 K, Tmin = 400 K

∴ \({{\rm{T}}_2} = {{\rm{T}}_4} = \sqrt {{{\rm{T}}_3} \times {\rm{\;}}{{\rm{T}}_1}} = \sqrt {900\; \times 400} = 600\;K\)

\({{\rm{w}}_{{\rm{net}}}} = {\rm{\;}}{{\rm{C}}_{\rm{p}}}{\rm{\;}}\left[ {\left( {{{\rm{T}}_3} - {{\rm{T}}_2}} \right) - \left( {{{\rm{T}}_4} - {{\rm{T}}_1}} \right)} \right]\)

\({{\rm{w}}_{{\rm{net}}}} = {\rm{\;}}{{\rm{C}}_{\rm{p}}}\left[ {\left( {900 - 600} \right) - \left( {600 - 400} \right)} \right]\)

wnet = Cp (300 – 200) = 100 Cp

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