Question
Download Solution PDFThe maximum height of a siphon for a fluid of specific gravity ρ under atmospheric conditions is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe General height of the siphon
\({h_B} = \frac{{{p_{atm}}}}{{ρ g}} - \frac{{V_2^2}}{{2g}}\)
ρ is the density of the fluid.
Specific gravity = ρfluid/ρwater = ρfluid/1000
Here specific gravity is given as ρfluid = SG × 1000 = ρ × 1000
∴ \({h_B} = \frac{{{p_{atm}}}}{{1000ρ g}} - \frac{{V_2^2}}{{2g}}\)
2 is the highest point of siphon.
For maximum height
VB = 0
patm= 1.01325 bar, g = 9.81 m/s2
pppjj\({h_B} = \frac{{{p_{atm}}}}{{1000ρ g}} = \frac{{10}}{ρ }\;meters\)
Last updated on Mar 27, 2025
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