The h₁₁ and h₂₂ of a standard T-network with series impedances 2Ω and 7Ω, and shunt branch impedance of 3Ω are

The T - network given in the question can be drawn as follows:

By applying KVL at port 1 and 2, we get

V₁ = 5I₁ + 3I₂   ---(1)

V₂ = 3I₁ + 10I₂   ---(2)

By using the above two relations, H parameters can be found as follows:

Putting V₂ = 0 in equation (2), we get

\(I_2=-\frac{3}{10}I_1\) ---(3)

Putting the value of equation (3) in equation (1), we get:

\(V_1=5I_1-\frac{9}{10}I_1\)

\(V_1 = \frac{41}{10} I_1\)

V₁ = 4.1 I₁

\(h_{11}=\frac{V_1}{I_1}\)

h₁₁ = 4.1 Ω 

Putting I₁ = 0 in equation (2), we get

\(h_{22}=\frac{I_2}{V_2} = 0.1 ~mho\)

The best option is 3.