Which of the following is hybrid parameter h22 of a two-port network?

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UGC NET Paper 2: Electronic Science June 2019 Official Paper
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  1. \(\left.{\frac{{{I_2}}}{{{V_2}}}}\right|_{{I_1}=0}\)
  2. \(\left.{\frac{{{V_2}}}{{{V_1}}}}\right|_{{I_2}=0}\)
  3. \(\left.{\frac{{{V_2}}}{{{I_2}}}}\right|_{{V_1}=0}\)
  4. \(\left.{\frac{{{I_2}}}{{{I_1}}}}\right|_{{V_1}=0}\)

Answer (Detailed Solution Below)

Option 1 : \(\left.{\frac{{{I_2}}}{{{V_2}}}}\right|_{{I_1}=0}\)
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Detailed Solution

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h-parameter representation of a two-port network is as follows:

V1 = h11 I1 + h12 V2

I2 = h21 I1 + h22 V2

where

\(h_{11}={\left.{\frac{{{V_1}}}{{{I_1}}}}\right|_{{V_2}=0}}~;~{h_{12}}={\left.{\frac{{{V_1}}}{{{V_2}}}}\right|_{{I_1} = 0}}\)

\(h_{21}={\left.{\frac{{{I_2}}}{{{I_1}}}}\right|_{{V_2}= 0}}~and~{h_{22}}={\left.{\frac{{{I_2}}}{{{V_2}}}} \right|_{{I_1}=0}}\)

26 June 1

ABCD Parameter:

F2 S.B Madhu 07.05.20 D16

There are four variables V1, V2, I1, and I2 in a two-port network as shown in the figure

\(\left[ {\begin{array}{*{20}{c}} {{V_1}}\\ {{I_1}} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} A&B\\ C&D \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{V_2}}\\ { - {I_2}} \end{array}} \right]\)

Where,

\(A= {\left. {\frac{{{V_1}}}{{{V_2}}}} \right|_{{I_2} = 0}}\)

\(B=- {\left. {\frac{{{V_1}}}{{{I_2}}}} \right|_{{V_2} = 0}}\)

\(C= {\left. {\frac{{{I_1}}}{{{V_2}}}} \right|_{{I_2} = 0}}\)

\(D=\; - {\left. {\frac{{{I_1}}}{{{I_2}}}} \right|_{{V_2} = 0}}\)

Y parameter:

\(\left[ {\begin{array}{*{20}{c}} {{I_1}}\\ {{I_2}} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} {{Y_{11}}}&{{Y_{12}}}\\ {{Y_{21}}}&{{Y_{22}}} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{V_1}}\\ {{V_2}} \end{array}} \right]\)

I1 = V1 Y11 + V2 Y12

I2 = V1 Y21 + V2 Y22

Z Parameters:

\(\left[ {\begin{array}{*{20}{c}} {{V_1}}\\ {{V_2}} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} {{Z_{11}}}&{{Z_{12}}}\\ {{Z_{21}}}&{{Z_{22}}} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{I_1}}\\ {{I_2}} \end{array}} \right]\)

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