Question
Download Solution PDFఒక రాగి తీగ చతురస్రం రూపంలో వంగినప్పుడు 121 సెం.మీ2 వైశాల్యం కలిగి ఉంది. అదే తీగ వృత్తం రూపంలో వంగి ఉంటే, వృత్తం యొక్క వైశాల్యాన్ని కనుగొనండి. (π = 22/7 ఉపయోగించండి)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFచతురస్రం యొక్క వైశాల్యం = 121 సెం.మీ2
చతురస్రం యొక్క భుజం ‘a’ సెం.మీ అనుకుందాం,
⇒ a2 = 121 సెం.మీ2
⇒ a = 11 సెం.మీ
రాగి తీగ పొడవు = చతురస్రం యొక్క చుట్టుకొలత
⇒ పొడవు = 4 × 11 = 44 సెం.మీ
రాగి తీగ పొడవు = వృత్తం యొక్క చుట్టుకొలత
⇒ 2πr = 44 సెం.మీ
⇒ 2 × 22/7 × r = 44 సెం.మీ
⇒ r = 7 సెం.మీ
వృత్తం యొక్క వైశాల్యం = πr2
∴ వైశాల్యం = 22/7 × 7 × 7 = 154 సెం.మీ2Last updated on Jun 26, 2025
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