Question
Download Solution PDFदिलेल्या आकृतीमध्ये ABCD हा समभुज चौकोन आहे, x चे मूल्य आहे.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
∠CAB = 40 °, ∠BDC = x°
संकल्पना:
समभुज चौकोन ABCD मध्ये, सर्व बाजू समान असतात.
समभुज चौकोनाच्या समीप कोनांची बेरीज 180° आहे
गणना:
∠D = 2 × ∠BDC = 2x [ कर्ण समभुज चौकोनातील कोनांना दुभाजक करतात]
∠A = 2 × ∠CAB = 2 × 40 = 80°
आता,
∠CAB + ∠D = 180°
⇒ 80°+ 2x = 180°
⇒ x = 100/2 = 50°
∴ x चे मूल्य 50° आहे.
Last updated on Jun 17, 2025
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