Question
Download Solution PDFIn Young’s double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In Young’s double slit experiment two coherent sources of light are placed at a very small distance away from each other. It is used to understand wave theory of light.
Constructive and destructive interference of light is shown.
Calculation:
Fringe width \(β = \frac{{\lambda D}}{d}\)
Now, \(d' = \frac{d}{2}\) and D' = 2D
So, \(β ' = \frac{{\lambda (2D)}}{{d/2}} = \frac{{4\lambda D}}{d}\)
β' = 4β
Last updated on Jun 16, 2025
-> NTA has released the NEET Scorecard 2025 on the official website.
-> NEET Toppers List 2025 is now available. Candidates can check the names, scores, and all India ranks of the highest scorers.
-> NEET final answer key 2025 has been made available on June 14, 2025 on the official website for the students to check.
->NEET 2025 exam is over on May 4, 2025.
-> The NEET 2025 Question Papers PDF are now available.
-> NTA has changed the NEET UG Exam Pattern of the NEET UG 2025. Now, there will be no Section B in the examination.
-> Candidates preparing for the NEET Exam, can opt for the latest NEET Mock Test 2025.
-> NEET aspirants can check the NEET Previous Year Papers for their efficient preparation. and Check NEET Cut Off here.