In case of a Squirrel-cage induction motor using three-phase bridge inverter, which one of the following statements is correct for speed control?  

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UPSC IES Electrical 2022 Prelims Official Paper
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  1. if frequency increases, then starting torque decreases with constant supply voltage.
  2. if frequency increases, then starting torque increases with constant supply voltage.
  3. if frequency decreases, then starting torque increases with constant supply voltage.
  4. both (a) and (c)

Answer (Detailed Solution Below)

Option 4 : both (a) and (c)
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Detailed Solution

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Solution:-
In an induction motor, approximate torque eqn considering stator impedance is negligible is given below:-

\(\rm T=\frac{3}{\omega_s}\cdot\frac{v^2}{\left(\frac{r_2}{s}\right)^2+X_2^2}\cdot\frac{r_2}{s}\)

At starting, s = 1

∴ \(\rm T_{st}=\frac{3}{\omega_s}\cdot\frac{v^2}{r_2^2+x_2^2}\cdot r_2\)

∴ \(\rm r_2^2<<x_2^2\)

∴ \(\rm T_{st}=\frac{3}{\omega_s}\cdot\frac{v^2}{x_2^2}\cdot r_2\)

\(\rm T_{st}=\frac{3}{2\pi f}\cdot\frac{v^2}{x_2^2}\cdot r_2\)

∴ x ∝ f

∴ \(\rm T_{st}=\frac{3}{2\pi}\cdot\frac{v^2}{x_2^2}\cdot r_2\)

given voltage is constant

∴ \(\rm T_{st}\propto\frac{1}{f^3}\)

Hence, if frequency increases, then starting torque decreases and if frequency decreases, then starting torque increases.

Hence, both option 1 and option 3 are correct.

The correct answer is option "4"

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