In a class of 50 students, it was found that 30 students read "Hitavad", 35 students read "Hindustan" and 10 read neither. How many students read both "Hitavad" and "Hindustan" newpapers?

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NIMCET 2020 Official Paper
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  1. 25
  2. 35
  3. 15
  4. 30

Answer (Detailed Solution Below)

Option 1 : 25
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Detailed Solution

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Concept:

Let A and B denote two sets of elements.

  • n(A) and n(B) are the number of elements present in set A and B respectively.
  • n(A ⋃ B) is the total number of elements present in either set A or B.
  • n(A ⋂ B) is the number of elements present in both the sets A and B.
  • n(A ⋃ B) = n(A) + n(B) - n(A ⋂ B)

 

Calculations:

Let A be the set of students who read "Hitavad" and B the set of students who read "Hindustan".

From the given information:

n(A ⋃ B) = 50 - 10 = 40.

n(A) = 30.

n(B) = 35.

By using n(A ⋃ B) = n(A) + n(B) - n(A ⋂ B), we get:

40 = 30 + 35 - n(A ⋂ B)

⇒ n(A ⋂ B) = 25.

∴ The number of students who read both "Hitavad" and "Hindustan" newpapers is n(A ⋂ B) = 25.

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