If the points (1, 3, -2), (2, λ, 1) and (3, 4, -1) are collinear then λ is

  1. 1
  2. 2
  3. 3
  4. 4

Answer (Detailed Solution Below)

Option 1 : 1
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Detailed Solution

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Concept:

For the points (x1, y1, z1), (x2, y2, z2) and (x3, y3, z3) to be collinear

\(\rm \begin{vmatrix} x_1 & y_1 &z_1 \\ x_2& y_2& z_2 \\ x_3& y_3& z_3 \end{vmatrix} = 0\)

Calculation:

The given points are (1, 3, -2), (2, λ, 1) and (3, 4, -1)

The equation of the plane will be 

\(\rm \begin{vmatrix} 1 &3 &-2\\ 2& λ& 1\\ 3&4& -1 \end{vmatrix} = 0\)

⇒ 1(-λ - 4) - 3(-2 - 3) + (-2)(8 - 3λ) = 0

⇒ 5λ - 4 + 15 - 16 = 0

⇒ 5λ = 5

⇒ λ = 1

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