Question
Download Solution PDFIf E1 and E2 are two mutually exclusive events such that P(E1) = 4/7 and P(E2) = 1/4 then P(E1 ∪ E2) = ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
- If A and B are mutually exclusive events i.e A ∩ B = ϕ, then P(A ∪ B) = P(A) + P(B)
CALCULATION:
Given: E1 and E2 are two mutually exclusive events such that P(E1) = 4/7 and P(E2) = 1/4
Here, we have to find P(E1 ∪ E2)
∵ E1 and E2 are two mutually exclusive events i.e E1 ∩ E2 = ϕ
As we know that, if A and B are mutually exclusive events i.e A ∩ B = ϕ, then P(A ∪ B) = P(A) + P(B)
⇒ P(E1 ∪ E2) = P(E1) + P(E2) = 4/7 + 1/4 = 23/28
Hence, correct option is 1.
Last updated on Jun 11, 2025
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