Question
Download Solution PDFHow much charge is required for the reduction of \(\rm MnO^-_4 \ to\ Mn^{2+}\) ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFor redox change
\(\mathrm{MnO}_4^{-} \rightarrow \mathrm{Mn}^{2+}\)
n-factor = 5
neq = nmol × n-factor
= 1 × 5
= 5
Charge required in Faraday = Number of neq
= 5 F
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