किसके बराबर है (N ≠ 1)?

This question was previously asked in
NDA (Held On: 22 April 2018) Maths Previous Year paper
View all NDA Papers >

Answer (Detailed Solution Below)

Option 1 :
Free
UPSC NDA 01/2025 General Ability Full (GAT) Full Mock Test
150 Qs. 600 Marks 150 Mins

Detailed Solution

Download Solution PDF

संकल्पना:

प्रयोग किया गया सूत्र:

  • Loga M + loga N = loga (MN)

 

क्रमगुणित:

  • n! = 1 × 2 × 3 × ⋯ × (n – 1) × n

 

गणना:

  का प्रयोग करने पर 

= logN (2 × 3 × ⋯ × 100)

= logN (100!)

Latest NDA Updates

Last updated on Jul 8, 2025

->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.

->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

More Relations and Functions Questions

Hot Links: teen patti tiger teen patti vip teen patti rules