Question
Download Solution PDFएक सॉफ्टवेयर इंजीनियर एक त्रुटि X को सही ढंग से डीबग करेगा, इसकी संभावना 80% है। सही डिबगिंग के बाद त्रुटि X वाला सॉफ़्टवेयर क्रैश होने की संभावना 30% है। गलत डीबगिंग द्वारा सॉफ़्टवेयर के क्रैश होने की संभावना 70% है। X त्रुटि वाला सॉफ़्टवेयर क्रैश हो गया। इसकी त्रुटि के सही ढंग से डिबग होने की प्रायिकता है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है
P(A I B) = 30% = 0.3
P(A) = 80% = 0.8
P(B I A’) = 70% = 0.7
P(A’) = 100% - 80% = 2-0% = 0.2
सूत्र
P(A I B) = P(A I B). P(A)/P(B) = [P(A I B). P(A)]/[P(A I B). P(A) + P(B I A’) P(A’)]
गणना
P(A I B) = (0.3 × 0.8)/(0.3 × 0.8 + 0.7 + 0.2)
⇒ 0.24/(0.24 + 0.14)
⇒ 0.24/0.38
∴ इसके सही ढंग से त्रुटिपूर्ण होने की प्रायिकता 12/19 हैLast updated on Jul 8, 2025
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