Question
Download Solution PDF\(\rm \frac{(a-b+c)^2-(a-b-c)^2}{b-a}\)का मान किसके बराबर है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFप्रयुक्त सूत्र-
a2 - b2 = (a - b)(a + b)
स्पष्टीकरण -
हमारे पास है: \(\rm \frac{(a-b+c)^2-(a-b-c)^2}{b-a}\)
= \(\rm \frac{(a-b+c-(a-b-c))(a-b+c+(a-b-c))}{b-a}\)
= \(\rm \frac{(a-b+c-a+b+c)(a-b+c+a-b-c)}{b-a}\)
= \(\rm \frac{(c+c)(a-b+a-b)}{b-a}\)
= \(\rm \frac{(2c)(2a-2b)}{b-a} = \rm \frac{(2c)\times -2(b-a)}{b-a} = -4c\)
अतः विकल्प (1) सही उत्तर है।
Last updated on Apr 30, 2025
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