Question
Download Solution PDFPQRS एक समचतुर्भुज है। इसकी प्रत्येक भुजा 40 सेमी है। यदि PR = 64 सेमी और QS = (8x + 8) है। तब, x का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPR = 64 सेमी
इस प्रकार, PO = RO = 32 सेमी
QS = (8x + 8) सेमी
इस प्रकार, QO = OS = (4x + 4) सेमी
Δ SOR में –
\(S{R^2} = S{O^2} + R{O^2}\)
⇒ \({40^2} = {\left( {4{\rm{x}} + 4} \right)^2} + {\left( {32} \right)^2}\)
⇒ 402 – 322 = (4x + 4)2
⇒ 4x + 4 = 24
⇒ 4x + 4 = 24
⇒ 4x = 20
⇒ x = 5 सेमी
Last updated on Jul 7, 2025
-> The UPSC CDS Exam Date 2025 has been released which will be conducted on 14th September 2025.
-> Candidates can now edit and submit theirt application form again from 7th to 9th July 2025.
-> The selection process includes Written Examination, SSB Interview, Document Verification, and Medical Examination.
-> Attempt UPSC CDS Free Mock Test to boost your score.
-> Refer to the CDS Previous Year Papers to enhance your preparation.