Question
Download Solution PDFयदि sec θ + cos θ = 32 है, तब sec2 θ+ cos2 θ का मान कितना है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFप्रयुक्त सूत्र:
(a + b)2 = a2 + b2 + 2ab
गणना
sec θ + cos θ = 32
दोनों पक्षों का वर्ग करने पर:
(sec θ + cos θ)2 = sec2 θ+ cos2 θ + 2 sec θ cos θ
⇒ 1024 - 2 = sec2 θ+ cos2 θ
⇒ sec2 θ+ cos2 θ = 1022
समीकरण का मान 1022 है।
Last updated on Jul 22, 2025
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