Question
Download Solution PDFयदि 2 cot θ = 3 है, तो
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
2cotθ = 3
प्रयुक्त सूत्र:
Sinθ = P/H
Cosθ = B/H
Tanθ = P/B
Cotθ = B/P
H2 = P2 + B2
जहाँ P = कर्ण
B = आधार
H = ऊँचाई
गणना:
2cotθ = 3
⇒ cotθ = 3/2
(Cotθ = B/P) से तुलना करने पर, हमें प्राप्त होता है
⇒ B = 3
⇒ P = 2
पाइथागोरस प्रमेय के अनुसार
⇒ H2 = P2 + B2
⇒ H2 = 22 + 32
⇒ H = √13
⇒ Sinθ = 2/√13
⇒ Cosθ = 3/√13
⇒ Tanθ = 2/3
दिए गए समीकरण में सभी मानों को रखने पर:
⇒ (2 - 2)/(2 + 3)
⇒ 0
व्यंजक का मान 0 है।
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