Question
Download Solution PDFयदि 12 + 22 + 32 + ... + 102 = 385 है, तो (22 + 42 + 62 + ... + 202) किसके बराबर है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है :
12 + 22 + 32 + ... + 102 = 385
हल :
⇒ ( 22 + 42 + 62 + ........ + 202 ) :
⇒ ( 1 × 2 )2 + ( 2 × 2 )2 + ............. + ( 2 × 10 )2
⇒ ( 22 × 12 ) + ( 22 × 22 ) + ....... + ( 22 × 102 )
⇒ 22 × ( 12 + 22 + 32 + ... + 102 )
⇒ 4 × 385
⇒ 1540
अतः, सही उत्तर "1540" है।
Last updated on Jul 8, 2025
->HSSC CET Exam Date 2025 is 26th and 27th July 2025.
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