Question
Download Solution PDFIf 12 + 22 + 32 + ... + 102 = 385, then (22 + 42 + 62 + ... + 202) is equal to :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven :
12 + 22 + 32 + ... + 102 = 385
Solution :
⇒ ( 22 + 42 + 62 + ........ + 202 ) :
⇒ ( 1 × 2 )2 + ( 2 × 2 )2 + ............. + ( 2 × 10 )2
⇒ ( 22 × 12 ) + ( 22 × 22 ) + ....... + ( 22 × 102 )
⇒ 22 × ( 12 + 22 + 32 + ... + 102 )
⇒ 4 × 385
⇒ 1540
Hence the correct answer is "1540".
Last updated on Jul 7, 2025
->HSSC CET Exam Date 2025 is 26th and 27th July 2025 (Tentative).
->The Haryana HSSC CET 2025 Exam will be held for two days in 4 shifts.
->HSSC CET Application Deadline 2025 was 14th June till 11:59 PM.
->Earlier, Haryana CET Group C Notice for EWS Certificate was out. A valid format of EWS Certificate has been given in the Notice.
-> Haryana CET Group C Notification 2025 was out on 26th May 2025.
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