Question
Download Solution PDF15sin θ + 20cos θ का अधिकतम मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
यदि त्रिकोणमितीय अनुपात 'asin θ + bcos θ' के रूप में है।
तो अधिकतम मान = \(\rm \sqrt {a^2+b^2}\)
और न्यूनतम मान = - \(\rm \sqrt {a^2+b^2}\)
गणना:
15sin θ + 20cos θ
यहाँ a = 15 और b = 20
तो अधिकतम मान = \(\rm \sqrt {{15}^2+20^2}\)
= \(\sqrt{225+400}\)
= √(625)
= 25
∴ 15sin θ + 20cos θ का अधिकतम मान 25 है।
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