चार प्रवाह चैनलों और सोलह समविभव पात वाले प्रवाह जाल के आकृति गुणक की गणना करें।

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PGCIL DT Civil 5 May 2023 Official Paper
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  1. 0.25
  2. 2
  3. 4
  4. 0.5

Answer (Detailed Solution Below)

Option 1 : 0.25
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Detailed Solution

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व्याख्या:

आकार गुणक (केवल सीमा शर्तों पर निर्भर करता है)

S = \(\frac{{{N_f}}}{{{N_d}}}\)

S = आकार गुणक

Nf = प्रवाह चैनलों की संख्या

Nd = समविभव पात की संख्या

गणना:

दिया गया:

Nf = 4, Nd = 16

आकार गुणक

S = \(\frac{{{N_f}}}{{{N_d}}}\) = \({4 \over 16} = {1\over 4}\) = 0.25

Additional Informationसीपेज निर्वहन निम्न द्वारा दिया जाता है,

\(q = KH\frac{{{N_f}}}{{{N_d}}}\)

जहाँ,

K = पारगम्यता का गुणांक

H = दाबोच्चता जिसके नीचे प्रवाह हो रहा है

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