For the reaction K + Br2 → KBr + Br, which follows the harpoon mechanism, the reactive cross section is closest to

(Use  = 2.3 × 10−28 J m, Ionization energy of K = 422.5 kJ mol−1, electron affinity of Br2 = 250 kJ mol−1 and NA = 6 × 1023 mol−1)

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CSIR-UGC (NET) Chemical Science: Held on (15 Dec 2019)
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  1. 50 × 10−18 m2
  2. 2 × 10−18 m2
  3. 64 × 10−18 m2
  4. 16 × 10−18 m2

Answer (Detailed Solution Below)

Option 2 : 2 × 10−18 m2
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Detailed Solution

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Concept:

Harpoon mechanism:-

One electron from the metal atom jumps to the nonmetal atom when two reactant molecules—one metal and one nonmetal—approach each other at a distance R (the radius of the cross-section where the collision occurs). The process is known as the Harpoon mechanism, and that electron is known as the Harpoon. Following that, non-metals become negatively charged ions, whereas metals become positively charged ions.

     K + Br2 → KBr + Br

When K approaches Br the valence electron(Harpoon) of K moves into Br.

This mechanism involves the following interactions;

  • Ionization Energy ( )
  • Electron affinity ( )
  • Coulombic interaction ( , R= separation between K+  and Br-)

 

So the reaction will be energetically favorable when 

Example:

  K + Br2 → KBr + Br

According to the theory,

 , (where R= radius of cross-section in which reaction occurs,  rand r= radius of each reactant molecule

  )

Explanation:-

=

=

Area of cross-section

2 × 10−18 m2

Conclusion:-

Hence the correct answer is 2 × 10−18 m2.

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