Find general solution of tan x = \(\sqrt 3\)

  1. nπ + \(\rm \frac {\pi}{3}\), n ∈ Z
  2. nπ - \(\rm \frac {\pi}{3}\), n ∈ Z
  3. nπ + \(\rm \frac {\pi}{6}\), n ∈ Z
  4. nπ ± \(\rm \frac {\pi}{3}\), n ∈ Z

Answer (Detailed Solution Below)

Option 1 : nπ + \(\rm \frac {\pi}{3}\), n ∈ Z
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Detailed Solution

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Concept:

General solution of some standard trigonometric equations:

Equations

Solutions

Conditions

 sin θ = sin α

 θ = nπ + (-1)n α

 α ∈ [-π/2, π/2] and n ∈ z

 cos θ = cos α

 θ = 2nπ ± α

 α ∈ [0, π] and n ∈ z 

 tan θ = tan α

 θ = nπ + α

 α ∈ (-π/2, π/2) and n ∈ z

 

Calculation:

Given: tan x = \(\sqrt 3\)

⇒ tan x = tan \(\rm \frac {\pi}{3}\)

As we know, If tan θ = tan α then θ = nπ + α

Therefore, x = nπ + \(\rm \frac {\pi}{3}\) 

Hence, the general solution of tan x = \(\sqrt 3\) is nπ + \(\rm \frac {\pi}{3}\), n ∈ Z.

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