Consider the control system which has a root locus plot as given. The open loop transfer function is given by:

F2 Mrunal Engineering 03.10.2022 D1

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UPPCL AE Electrical 2 April 2022 Official Paper (Shift 2)
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  1. KS(S+1)(S+2)(S+3)
  2. K(S+3)S(S+1)(S+4)
  3. K(S+3)(S+1)(S+2)
  4. KS(S+1)(S+2)

Answer (Detailed Solution Below)

Option 2 : K(S+3)S(S+1)(S+4)
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Detailed Solution

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Calculation:

F2 Mrunal Engineering 03.10.2022 D1

In the given figure, there are three poles and one zero in the root locus.

Among all the options, only option 2 consists of three poles and one zero.

Hence, option 2 is correct.

Additional Information G(s)H(s) = K(S+3)S(S+1)(S+4)

The centroid is given by:

σc=14(3)2=1

The angle of asymptotes is given by:

=(2k+1)180PZ where, k=0,1 ...(P-Z-1)

=(2×0+1)1802=90 and =(2×1+1)1802=270

The breakaway point is given by:

dkds=0

dds(s(s+1)(s+4)(s+3))=0

s = -0.51, -3.29 ± j 1.071

s = -0.51 is a valid breakaway point.

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