Question
Download Solution PDFA photon and an electron (mass m) have the same energy E. What is the ratio (λphoton / λelectron) of their de Broglie wavelengths? (c is the speed of light)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
The de-Brogile wavelength is given by: λ = h / √(2mE)
For electron: λe = h / √(2mE)
For photon: E = pc ⇒ λPh = hc / E
⇒ λe / λPh = (h / √(2mE)) × (E / hc) = √(E / 2m) × (1 / c)
⇒ λPh / λe = \(c\sqrt{\frac{2m}{E}}\)
The correct option is 3).
Last updated on Jun 16, 2025
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