Question
Download Solution PDFA 50 Hz, 3-phase synchronous generator has inductance per phase of X mH. The capacitance of the generator and circuit breaker is 0.002 μF. If the natural frequency of oscillation is 29 kHz, find the value of inductance X
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula Used:
Natural Frequency of Oscillation (f) = \( \frac{1}{{2\pi \sqrt {LC} }} \) Hz
Where,
L is inductance in H
C is capacitance in F
Calculation:
We have,
C = 0.002 μF
f = 29 kHz
From the above concept,
L = \(\frac{1}{4\pi ^2f^2C}\)
or, L = \(\frac{1}{4\pi^2\times 29k^2 \times 0.002\times 10^{-6}}\) = 15 mH
X = L = 15 mH
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