Logical Connectives MCQ Quiz in తెలుగు - Objective Question with Answer for Logical Connectives - ముఫ్త్ [PDF] డౌన్లోడ్ కరెన్
Last updated on Apr 5, 2025
పొందండి Logical Connectives సమాధానాలు మరియు వివరణాత్మక పరిష్కారాలతో బహుళ ఎంపిక ప్రశ్నలు (MCQ క్విజ్). వీటిని ఉచితంగా డౌన్లోడ్ చేసుకోండి Logical Connectives MCQ క్విజ్ Pdf మరియు బ్యాంకింగ్, SSC, రైల్వే, UPSC, స్టేట్ PSC వంటి మీ రాబోయే పరీక్షల కోసం సిద్ధం చేయండి.
Latest Logical Connectives MCQ Objective Questions
Top Logical Connectives MCQ Objective Questions
Logical Connectives Question 1:
Consider the following TRUTH table:
|
Y |
Z |
Y □ Z |
|
0 |
0 |
0 |
|
0 |
1 |
1 |
|
1 |
0 |
0 |
|
1 |
1 |
0 |
|
Y |
Z |
Y ⊗ Z |
|
0 |
0 |
1 |
|
0 |
1 |
0 |
|
1 |
0 |
1 |
|
1 |
1 |
0 |
(p □ q) ∨ (p ⊗ q) ≡
Answer (Detailed Solution Below)
Option 1 : \(p \to \bar q\)
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Logical Connectives Question 1 Detailed Solution
\(\begin{array}{l} p\; □ \;q \equiv \bar pq\\ p ⊗ q = \bar q\\ \therefore \bar pq + \bar q = \left( {\bar p + \bar q} \right)\left( {q + \bar q\;} \right) \equiv \bar p + \bar q\\ \equiv p \to \bar q \end{array}\)
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Logical Connectives Question 2:
Diamonds and pearls are precious.
WFF for this statement is:
Given
D(x) : x is a diamond
P (x) : x is a pearl
T(x) : x is preciousAnswer (Detailed Solution Below)
Option 2 : \(\forall x\left[ {\left( {D\left( x \right) \vee P\left( x \right)} \right) \to T\left( x \right)} \right]\)
Logical Connectives Question 2 Detailed Solution
If x is either a diamond or a pearl then it’s is precious.
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Logical Connectives Question 3:
Consider the following Truth Table
|
A |
B |
Y |
|
0 |
0 |
0 |
|
0 |
1 |
1 |
|
1 |
0 |
0 |
|
1 |
1 |
1 |
Y =
Answer (Detailed Solution Below)
Option 2 : B
Logical Connectives Question 3 Detailed Solution
AB + B = (A + 1)B = B
Also Y = B
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Logical Connectives Question 4:
|
A |
B |
F(A, B) |
|
F |
F |
T |
|
F |
T |
T |
|
T |
F |
F |
|
T |
T |
T |
From the given truth table F(A, B) is equivalent to:
Answer (Detailed Solution Below)
Option 1 : \(\bar B \to \bar A\)
Logical Connectives Question 4 Detailed Solution
\(F\left( {A,B} \right) \equiv A \to B \equiv \bar B \to \bar A\)
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