Frequency Domain Specifications MCQ Quiz in मल्याळम - Objective Question with Answer for Frequency Domain Specifications - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Last updated on Mar 22, 2025

നേടുക Frequency Domain Specifications ഉത്തരങ്ങളും വിശദമായ പരിഹാരങ്ങളുമുള്ള മൾട്ടിപ്പിൾ ചോയ്സ് ചോദ്യങ്ങൾ (MCQ ക്വിസ്). ഇവ സൗജന്യമായി ഡൗൺലോഡ് ചെയ്യുക Frequency Domain Specifications MCQ ക്വിസ് പിഡിഎഫ്, ബാങ്കിംഗ്, എസ്എസ്‌സി, റെയിൽവേ, യുപിഎസ്‌സി, സ്റ്റേറ്റ് പിഎസ്‌സി തുടങ്ങിയ നിങ്ങളുടെ വരാനിരിക്കുന്ന പരീക്ഷകൾക്കായി തയ്യാറെടുക്കുക

Latest Frequency Domain Specifications MCQ Objective Questions

Top Frequency Domain Specifications MCQ Objective Questions

Frequency Domain Specifications Question 1:

Match the following

1) Resonant frequency        P)  ωn12ξ2+24ξ2+4ξ4
2) Bandwidth       Q)  ωn12ξ2
3) Resonant peak    R)  ωn1ξ2
4) Damping ratio S) 12ξ1ξ2
  T) 12Q

   

                                                          

 

  1. 1)Q,2)P,3)S,4)T

  2. 1)R,2)P,3)S,4)T

  3. 1)Q,2)P,3)R,4)T

  4. 1)R,2)P,3)Q,4)T

Answer (Detailed Solution Below)

Option 1 :

1)Q,2)P,3)S,4)T

Frequency Domain Specifications Question 1 Detailed Solution

Resonant frequency, ωr=ωn12ξ2

Damping Ratio ξ=12Q

Resonant Peak  Mr=12ξ1ξ2

Bandwidth BW=ωn12ξ2+24ξ2+4ξ4

Frequency Domain Specifications Question 2:

The unit step response of a second-order system is shown below

Gate EE Part test-2 Ques-22 Q-1

The resonant peak of the system is:

  1. 0.747
  2. 1.84
  3. 1.747
  4. 0.84

Answer (Detailed Solution Below)

Option 3 : 1.747

Frequency Domain Specifications Question 2 Detailed Solution

Given:

Maximum overshoot = 0.37

eζπ1ζ2=0.37

ζ=0.3

Resonant Peak:

Mr=12ζ1ζ2

Putting the value of ζ, we get

Mr = 1.747

Frequency Domain Specifications Question 3:

Match the following

1)         Resonant frequency               P)      ωn12ξ2+24ξ2+4ξ4

2)         Bandwidth                              Q)      ωn12ξ2

3)         Resonant peak                      R)      ωn1ξ2

4)         Damping ratio                        S)      12ξ1ξ2

                                                          T)      12Q

 

  1. 1)Q,2)P,3)S,4)T
  2. 1)R,2)P,3)S,4)T
  3. 1)Q,2)P,3)R,4)T
  4. 1)R,2)P,3)Q,4)T
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : 1)Q,2)P,3)S,4)T

Frequency Domain Specifications Question 3 Detailed Solution

Resonant frequency, ωr=ωn12ξ2

Damping Ratio ξ=12Q

Resonant Peak  Mr=12ξ1ξ2

Bandwidth BW=ωn12ξ2+24ξ2+4ξ4

Frequency Domain Specifications Question 4:

Range of ϕr with ξ variation is –

r = phase at resonant freq.)

  1. -90° to 0° 
  2. +90° to 0° 
  3. -180° to 0°       
  4. +180° to 0°
  5. -90° to 90° 

Answer (Detailed Solution Below)

Option 1 : -90° to 0° 

Frequency Domain Specifications Question 4 Detailed Solution

Range ξ is 0<ξ<1/2

ϕr|ξ=0=tan1[12ξ2ξ]=90

ϕr|ξ=12=tan1[12ξ2ξ]=0

Frequency Domain Specifications Question 5:

Frequency response of a second order system is given below. The value of K is ______

G(s)=K(36)s2+6s+36

GATE IN Control Systems Sunny Deepak images Q27a

Answer (Detailed Solution Below) 10

Frequency Domain Specifications Question 5 Detailed Solution

G(s)=K(36)s2+6s+36

characteristic equation:

s2 + 6s + 36 = 0

ω2n = 36 ⇒ ωn = 6 rad/sec

2ξωn = 6 ⇒ ξ = 0.5

From the given response,

Mr=203 

Mr=12ξ1ξ2for0ξ12 

=1forξ12 

203=K2(0.5)1(14) 

K34=203K=10 

Frequency Domain Specifications Question 6:

Range of ϕr with ξ variation is –

r = phase at resonant freq.)

  1. -90° to 0° 
  2. +90° to 0° 
  3. -180° to 0°       
  4. +180° to 0°

Answer (Detailed Solution Below)

Option 1 : -90° to 0° 

Frequency Domain Specifications Question 6 Detailed Solution

Range ξ is 0<ξ<1/2

ϕr|ξ=0=tan1[12ξ2ξ]=90

ϕr|ξ=12=tan1[12ξ2ξ]=0

Frequency Domain Specifications Question 7:

Phase at resonant frequency if ξ = 0.4 is 

  1. 66.42° 
  2. 64.12° 
  3. -66.42° 
  4. -64.12° 

Answer (Detailed Solution Below)

Option 4 : -64.12° 

Frequency Domain Specifications Question 7 Detailed Solution

ϕ=tan1[12ξ2ξ]

=64.12°

since control systems are Low pass filters that give more negative phase. So Ø = -64.12 degrees

Note :

Cos-1ξ  cannot be used here because this is resonance condition

Frequency Domain Specifications Question 8:

If damping ratio ξ = 0.8 then resonant peak is 

  1. 2.0833
  2. 1.041
  3. 1.1811
  4. 0.8
  5. None of the above 

Answer (Detailed Solution Below)

Option 5 : None of the above 

Frequency Domain Specifications Question 8 Detailed Solution

For ζ >12(=0.707), there is no resonant peak in the frequency response.

Frequency Domain Specifications Question 9:

If ωn =ωbthen damping ratio is – (ωb = bandwidth, ωn = natural freq.)

  1. 0
  2. 0.5
  3. 1
  4. 12
  5. 1.414

Answer (Detailed Solution Below)

Option 4 : 12

Frequency Domain Specifications Question 9 Detailed Solution

ωb=ωn(12ξ2)+4ξ44ξ2+2

For ξ=12 we will get ωn=ωb

Frequency Domain Specifications Question 10:

Consider the following systems:

System 1: G(s)=12s+1

System 2: G(s)=15s+1

The true statement regarding the system is

  1. Bandwidth of system 1 is greater than the bandwidth of system 2
  2. Bandwidth of system 1 is lower than the bandwidth of system 2
  3. Bandwidth of both the system are the same
  4. Bandwidth of both the systems are infinite
  5. All of the above

Answer (Detailed Solution Below)

Option 1 : Bandwidth of system 1 is greater than the bandwidth of system 2

Frequency Domain Specifications Question 10 Detailed Solution

System 1: G(s)=12s+1

Time constant (τ1) = 2 sec.

System 2: G(s)=15s+1

Time constant (τ2) = 5 sec

Bandwidth is inversely proportional to time constant.

So, bandwidth of system 1 is greater than the bandwidth of system 2.
Get Free Access Now
Hot Links: teen patti neta real teen patti teen patti plus teen patti master apk