Random Sequence of Alphabets MCQ Quiz - Objective Question with Answer for Random Sequence of Alphabets - Download Free PDF

Last updated on May 28, 2025

Latest Random Sequence of Alphabets MCQ Objective Questions

Random Sequence of Alphabets Question 1:

Refer to the following series of letters and symbols and answer the question.
(Left) M@R X Z $ I Q & D E A + C E # H O & T Y % E F S P G K(Right)
How many vowels are there, each of which is immediately preceded by a consonant and immediately followed by a vowel?

  1. 2
  2. 1
  3. 4
  4. 3

Answer (Detailed Solution Below)

Option 2 : 1

Random Sequence of Alphabets Question 1 Detailed Solution

Given series:

M@R X Z $ I Q & D E A + C E # H O & T Y % E F S P G K

Condition to be checked:

Vowels immediately preceded by a consonant and immediately followed by a vowel.

Consonant → Vowel → Vowel

Let's analyze the series for this pattern:

M@R X Z $ I Q & D E A + C E # H O & T Y % E F S P G K

  • D E A + (Yes, 'E' is a vowel, preceded by consonant 'D' and followed by vowel 'A')

Thus, there is 1 vowel that is immediately preceded by a consonant and immediately followed by a vowel.

Hence, the correct answer is "Option 2".

Random Sequence of Alphabets Question 2:

If each letters in the English alphabet is attached a value equal to its serial number in the alphabet, which among the following will have the highest sum of values of all its letters ?

  1. MATHS
  2. STATS
  3. HINDI
  4. CIVIL

Answer (Detailed Solution Below)

Option 2 : STATS

Random Sequence of Alphabets Question 2 Detailed Solution

Common Diagram 28.01.2020 D1

We need to find which of the given words has the highest sum of the values of all its letters.

1) MATHS

M = 13, A = 1, T = 20, H = 8,S = 19

Sum for MATHS = 13 + 1 + 20 + 8 + 19 = 61

2) STATS

S = 19, T = 20, A = 1, T = 20, S = 19

Sum for STATS = 19 + 20 + 1 + 20 + 19 = 79

3) HINDI

H = 8, I = 9, N = 14, D = 4, I = 9

Sum for HINDI = 8 + 9 + 14 + 4 + 9 = 44

4) CIVIL

C = 3, I = 9, V = 22, I = 9, L = 12

Sum for CIVIL = 3 + 9 + 22 + 9 + 12 = 55

Thus, The highest sum is 79, which belongs to the word STATS.

Hence, the correct answer is "Option 2".

Random Sequence of Alphabets Question 3:

Answer the question asked keeping in mind the following series. (Left side ) T N J T S Q S R W H F LH V Q W P N (Right side) Which letter is fourth to the right of the thirteenth letter from the left in the given sequence?

  1. N
  2. H
  3. P
  4. W

Answer (Detailed Solution Below)

Option 3 : P

Random Sequence of Alphabets Question 3 Detailed Solution

As per the given information;

Given Series: (Left) T N J T S Q S R W H F L H V Q W P N (Right)

T N J T S Q S R W H F L H V Q W P N 

  • The thirteenth letter from the left end:

(Left) T N J T S Q S R W H F L H V Q W P N (Right)

The 13th letter from the left end is 'H'.

  • The fourth letter to the right of the thirteenth letter from the left end:

(Left) T N J T S Q S R W H F L H V Q W P N (Right)

Starting from 'H' (the 13th letter from the left), the first letter to its right is 'V', the second is 'Q', the third is 'W', and the fourth is P'.

Therefore, the fourth letter to the right of the thirteenth letter from the left end is 'P'.

Hence, the correct answer is "Option 3".

Random Sequence of Alphabets Question 4:

Answer the question asked keeping in mind the following series.
(Left-hand side) L G M E L C Y 0 F Q N R S T U M K H (Right-hand side)
How many consonants are there in this series, each of which has a consonant immediately preceding and also a consonant immediately following?

  1. Six
  2. Four
  3. Nine
  4. Seven

Answer (Detailed Solution Below)

Option 4 : Seven

Random Sequence of Alphabets Question 4 Detailed Solution

Given series:

L G M E L C Y O F Q N R S T U M K H

Condition to be checked:

A consonant that is immediately preceded by a consonant and immediately followed by a consonant.

Consonant → Consonant → Consonant

L G M E L C YF Q N R S T U M K H

The consonants that satisfy the given condition are G, M, N, and K.

Thus there are Seven such consonants (G, C, Q, N, R, S, K) that are following the above conditions.

Hence,"Option 4" is the correct answer.

Mistake Points

Immediately preceding means immediately before or to come just before.

Immediately following means immediately after or to come just after.

Random Sequence of Alphabets Question 5:

Look at the following series of letters and symbols and answer the questions given below. Counting is to be done from left to right. (Left) X M U N O Q D L E J G E K V H R F N (Right) What is the second letter to the right of the seventh letter from the left in this series? 

  1. 1) G
  2. 2) E
  3. 3)R
  4. 4) V

Answer (Detailed Solution Below)

Option 2 : 2) E

Random Sequence of Alphabets Question 5 Detailed Solution

Given series: (Left) X M U N O Q D L E J G E K V H R F N (Right)

So, second letter to the right of the seventh letter from the left in this series → (Left) X M U N O Q D L E J G E K V H R F N (Right) → E

Hence, "Option 2" is the correct answer.

Top Random Sequence of Alphabets MCQ Objective Questions

This question is based on the following 3-letter words.

AIN, ONK, AST, EJO

If in each of the words, each letter is changed to the next letter in the English alphabetical order, how many words thus formed will have no vowel? 

  1. 3
  2. 2
  3. 4
  4. 1

Answer (Detailed Solution Below)

Option 4 : 1

Random Sequence of Alphabets Question 6 Detailed Solution

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The given letter clusters are,

AIN, ONK, AST, EJO

When each letter is changed to the next letter in the English alphabetical order, the words formed are

BJO, POL, BTU, FKP

From the above words, only one word doesn't have a vowel.

Hence, the correct answer is option 4).

If it is possible to make only one seven letter meaningful English word with the 1st, 4th, 5th, and 7th letter of the word PRIORITY and 3rd, 5th, and 6th letter of the word SECTOR, which of the following will be the first letter from left of that word? If no such word can be made give ‘X’ as the answer and if more than one such word can be made give ‘Y’ as the answer.

  1. P
  2. R
  3. Y
  4. O
  5. X

Answer (Detailed Solution Below)

Option 1 : P

Random Sequence of Alphabets Question 7 Detailed Solution

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Given words: PRIORITY and SECTOR

1st, 4th, 5th and 7th letter from the first word is: P, O, R, T 

3rd, 5th, and 6th letter from the second word is: C, O, R

Combining and jumbling first and second word we get: PROCTOR

Hence, the first letter will, be P.

Study the following arrangement of the English alphabet and answer the questions given below:

P M S K Q A B M N O P Q R W

If letters at even positions are replaced by a succeeding letter and letters at odd places are replaced by a preceding letter, then which letters will be twice in number in the new series?

  1. O, N and P
  2. O and P
  3. O, N, R and P
  4. O, N, R, B and P

Answer (Detailed Solution Below)

Option 3 : O, N, R and P

Random Sequence of Alphabets Question 8 Detailed Solution

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Given series: P M S K Q A B M N O P Q R W

1) Letters at even positions: M, K, A, M, O, Q, W

Succeeding letters: N, L, B, N, P, R, X

2) Letters at odd positions: P, S, Q, B, N, P, R

Preceding Letters: O, R, P, A, M, O, Q

New series: O, N, R, L, P, B, A, N, M, P, O, R, Q, X

Letters appearing twice in the new series: O, N, R and P

Hence, the answer is option 3.

Refer to the letter and symbol series, and answer the question that follows.

(Left) K B # A @ S * B Q @ R V N % & S (Right)

How many letters are there between the element that is third from the right end and the element that is sixth from the left end of the given series?

  1. 8
  2. 5
  3. 7
  4. 6

Answer (Detailed Solution Below)

Option 2 : 5

Random Sequence of Alphabets Question 9 Detailed Solution

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The logic followed here is :

Given series: (Left) K B # A @ S * B Q @ R V N % & S (Right)

The element that is third from the right end is %

(Left) K B # A @ S * B Q @ R V N % & S (Right)

The element that is sixth from the left end of the given series is S

(Left) K B # A @ S * B Q @ R V N % & S (Right)

(Left) K B # A @ S * B Q @ R V N % & S (Right)

Thus, there are a total of 5 letters that are B, Q, R, V, N 

Hence, the correct answer is  "Option 2".

This question is based on the five, three-digit numbers given below.

(Left) 653 831 933 476 715 (Right)

(Example: 697 - first digit = 6, second digit = 9, third digit = 7)

NOTE: All operations to be done from left to right.

If 2 is added to the third digit of every number, in how many numbers will the third digit be exactly divided by the second digit of that number? 

  1. 2
  2. 3
  3. 1
  4. 4

Answer (Detailed Solution Below)

Option 2 : 3

Random Sequence of Alphabets Question 10 Detailed Solution

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Given three-digit numbers series:

(Left) 653 831 933 476 715 (Right)

If 2 is added to the third digit of every number, the new number formed is shown below:

655 833 935 478 717

In the new number series 655, 833, and 717, are the numbers where the third digit can be exactly divided by the second digit of that number.

Hence, the correct answer is option 2).

Rita is asked to rewrite the following series in the reverse order and after that delete the alternate letters from Y. She has to find out which letter will divide the new series in two equal parts Find the required letter?

ABCDEFGHIJKLMNOPQRSTUVWXYZ.

  1. N
  2. Q
  3. M
  4. H

Answer (Detailed Solution Below)

Option 1 : N

Random Sequence of Alphabets Question 11 Detailed Solution

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Given Series: ABCDEFGHIJKLMNOPQRSTUVWXYZ

Series in the reverse order: ZYXWVUTSRQPONMLKJIHGFEDCBA

Deleting alternate letters from Y in the above reverse series: Z X V T R P N L J H F D B

F1 Prashant 1.7.21 Pallavi D1

Therefore, the letter that divides the new series into two equal parts is N.

Hence, the correct answer is "N".

Refer to the following letter series and answer the question.

(Left) Q A Y S R E Z I L X B O P A R D I H O U K (Right)

How many such consonants are there, each of which is immediately preceded by a vowel and also immediately followed by a vowel?

  1. Two
  2. One
  3. Three
  4. Four

Answer (Detailed Solution Below)

Option 3 : Three

Random Sequence of Alphabets Question 12 Detailed Solution

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Given series: (Left) Q A Y S R E Z I L X B O P A R D I H O U K (Right)

Required pattern: Vowel → Consonant → Vowel

So, There are consonants are there, each of which is immediately preceded by a vowel and also immediately followed by a vowel.

Hence, "Option 3" is the correct answer.

How many D's are there in the  following series which are immediately followed by W but NOT immediately preceded by K?

KDCWKDWNKGDWDHKVDWZDW

  1. 1
  2. 2
  3. 3
  4. 4

Answer (Detailed Solution Below)

Option 3 : 3

Random Sequence of Alphabets Question 13 Detailed Solution

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Mistake Points

Immediately preceded by means immediately before or to come just before.

Immediately followed by means immediately after or to come just after.

The logic followed is:

Given series- 

KDCWKDWNKGDWDHKVDWZDW

Condition to be checked:

D which are immediately followed by W but NOT immediately preceded by K.

Not K → D → W

The series are given below

KDCWKDWNKGDWDHKVDWZDW

There are three pair of word which is GDW, VDW and ZDW.

Hence, "3" is the correct answer.

If in the word JUNIOR all the letters are arranged alphabetically, then the position of how many letter/letters will remain unchanged?

  1. One
  2. Two
  3. Three
  4. Four
  5. None

Answer (Detailed Solution Below)

Option 1 : One

Random Sequence of Alphabets Question 14 Detailed Solution

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Word: JUNIOR

Pic 1

Thus, only position of N remains unchanged.

Hence, one is the answer.

Comprehension:

Directions: Study the following alphabet series and answer the questions that follow:

P L M O K N I J B U H V Y G C T F X R D Z E S W A Q

How many letters are there in the English alphabetical series between the tenth letter from the right end and the eleventh letter from the left end?

  1. Two
  2. Five
  3. Seven
  4. One
  5. Four

Answer (Detailed Solution Below)

Option 4 : One

Random Sequence of Alphabets Question 15 Detailed Solution

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Left Side: P L M O K N I J B U H V Y G C T F X R D Z E S W A Q: Right Side

Tenth letter from the right end: F

Eleventh letter from the left end: H

In the English alphabetical series, there is only one letter between F and H → F, G, H.

Hence, the correct answer is ‘one’.
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