Initial or Final Value MCQ Quiz - Objective Question with Answer for Initial or Final Value - Download Free PDF
Last updated on Apr 23, 2025
Latest Initial or Final Value MCQ Objective Questions
Initial or Final Value Question 1:
During the first year, the strength of a school increased by 12%, in the second year it decreased by 12% and in the third year it increased by 10%. At the end of the third year its strength was nearly 10842. What was the strength at the beginning of the first year?
Answer (Detailed Solution Below)
Initial or Final Value Question 1 Detailed Solution
Given:
During the first year, the strength of school increased by 12%
It decreases by 12% in the second year and in the third year it increase by 10%
Strength at the end of third year is nearly 10842.
Calculation:
Let the initial strength be x.
After 1st year, strength
⇒ x × (1 + 12/100) = x × 1.12
After 2nd year, strength
⇒ x × 1.12 × (1 - 12/100) = x × 1.12 × 0.88
After 3rd year, strength,
⇒ x × 1.12 × 0.88 × (1 + 10/100)
⇒ x × 1.12 × 0.88 × 1.10
We know that after the 3rd year, the strength is 10842.
⇒ x × 1.12 × 0.88 × 1.10 = 10842
⇒ x = 10842 / (1.12 × 0.88 × 1.10)
⇒ x = 10842 / 1.08384
⇒ x ≈ 10000
∴ The strength of the school at the beginning of the first year was nearly 10000.
Shortcut Trick
Now, 6776 unit → 10842,
Then 6250 unit → \(\frac{10842}{6776 } \times 6250\) = 10000
Initial or Final Value Question 2:
A mask manufacturing company manufactured ‘X’ number of masks in 2018. It increased its manufacturing capacity by 30% in 2019 and further increased its manufacturing by 15% in 2020. In 2021, due to the machinery breakdown, its manufacturing declined by 40%. What is the value of ‘X’ if it manufactured 179400 masks in 2021?
Answer (Detailed Solution Below)
Initial or Final Value Question 2 Detailed Solution
Given:
30% increased in 2019
15% increased i. 2020
40% decreased in 2021
Mask manufactured in 2021 = 179400
Formula used:
Increased % = 100 + increased
Decreased % = 100 - decreased
Calculations:
⇒ Mask manufactured in 2019 = X × (100 + 30) = X × 130%
⇒ Mask manufactured in 2020 = (130%X) × (100 + 15) = 115% (130% of X)
⇒ Mask manufactured in 2021 = 115% (130% of X) × (100 - 40) = 60% ( 115%( 130% of X))
But according to the question,
⇒ Manufactured in 2021 = 179400
So,
⇒ 60%{115%(130% of X)} = 179400
⇒ \(\frac{X × 60×115×130}{100×100×100}= 179400\)
⇒ X = \(\frac{179400 × 100×100×100}{60×130×115} \)
⇒ X = 200000
⇒ Hence, The manufacture of mask in 2018 is 200000
Shortcut Trick
So, 897 unit → 179400
then, 1000 unit → 179400/897 × 1000 = 200000
Top Initial or Final Value MCQ Objective Questions
During the first year, the strength of a school increased by 12%, in the second year it decreased by 12% and in the third year it increased by 10%. At the end of the third year its strength was nearly 10842. What was the strength at the beginning of the first year?
Answer (Detailed Solution Below)
Initial or Final Value Question 3 Detailed Solution
Download Solution PDFGiven:
During the first year, the strength of school increased by 12%
It decreases by 12% in the second year and in the third year it increase by 10%
Strength at the end of third year is nearly 10842.
Calculation:
Let the initial strength be x.
After 1st year, strength
⇒ x × (1 + 12/100) = x × 1.12
After 2nd year, strength
⇒ x × 1.12 × (1 - 12/100) = x × 1.12 × 0.88
After 3rd year, strength,
⇒ x × 1.12 × 0.88 × (1 + 10/100)
⇒ x × 1.12 × 0.88 × 1.10
We know that after the 3rd year, the strength is 10842.
⇒ x × 1.12 × 0.88 × 1.10 = 10842
⇒ x = 10842 / (1.12 × 0.88 × 1.10)
⇒ x = 10842 / 1.08384
⇒ x ≈ 10000
∴ The strength of the school at the beginning of the first year was nearly 10000.
Shortcut Trick
Now, 6776 unit → 10842,
Then 6250 unit → \(\frac{10842}{6776 } \times 6250\) = 10000
A mask manufacturing company manufactured ‘X’ number of masks in 2018. It increased its manufacturing capacity by 30% in 2019 and further increased its manufacturing by 15% in 2020. In 2021, due to the machinery breakdown, its manufacturing declined by 40%. What is the value of ‘X’ if it manufactured 179400 masks in 2021?
Answer (Detailed Solution Below)
Initial or Final Value Question 4 Detailed Solution
Download Solution PDFGiven:
30% increased in 2019
15% increased i. 2020
40% decreased in 2021
Mask manufactured in 2021 = 179400
Formula used:
Increased % = 100 + increased
Decreased % = 100 - decreased
Calculations:
⇒ Mask manufactured in 2019 = X × (100 + 30) = X × 130%
⇒ Mask manufactured in 2020 = (130%X) × (100 + 15) = 115% (130% of X)
⇒ Mask manufactured in 2021 = 115% (130% of X) × (100 - 40) = 60% ( 115%( 130% of X))
But according to the question,
⇒ Manufactured in 2021 = 179400
So,
⇒ 60%{115%(130% of X)} = 179400
⇒ \(\frac{X × 60×115×130}{100×100×100}= 179400\)
⇒ X = \(\frac{179400 × 100×100×100}{60×130×115} \)
⇒ X = 200000
⇒ Hence, The manufacture of mask in 2018 is 200000
Shortcut Trick
So, 897 unit → 179400
then, 1000 unit → 179400/897 × 1000 = 200000
Initial or Final Value Question 5:
During the first year, the strength of a school increased by 12%, in the second year it decreased by 12% and in the third year it increased by 10%. At the end of the third year its strength was nearly 10842. What was the strength at the beginning of the first year?
Answer (Detailed Solution Below)
Initial or Final Value Question 5 Detailed Solution
Given:
During the first year, the strength of school increased by 12%
It decreases by 12% in the second year and in the third year it increase by 10%
Strength at the end of third year is nearly 10842.
Calculation:
Let the initial strength be x.
After 1st year, strength
⇒ x × (1 + 12/100) = x × 1.12
After 2nd year, strength
⇒ x × 1.12 × (1 - 12/100) = x × 1.12 × 0.88
After 3rd year, strength,
⇒ x × 1.12 × 0.88 × (1 + 10/100)
⇒ x × 1.12 × 0.88 × 1.10
We know that after the 3rd year, the strength is 10842.
⇒ x × 1.12 × 0.88 × 1.10 = 10842
⇒ x = 10842 / (1.12 × 0.88 × 1.10)
⇒ x = 10842 / 1.08384
⇒ x ≈ 10000
∴ The strength of the school at the beginning of the first year was nearly 10000.
Shortcut Trick
Now, 6776 unit → 10842,
Then 6250 unit → \(\frac{10842}{6776 } \times 6250\) = 10000
Initial or Final Value Question 6:
A mask manufacturing company manufactured ‘X’ number of masks in 2018. It increased its manufacturing capacity by 30% in 2019 and further increased its manufacturing by 15% in 2020. In 2021, due to the machinery breakdown, its manufacturing declined by 40%. What is the value of ‘X’ if it manufactured 179400 masks in 2021?
Answer (Detailed Solution Below)
Initial or Final Value Question 6 Detailed Solution
Given:
30% increased in 2019
15% increased i. 2020
40% decreased in 2021
Mask manufactured in 2021 = 179400
Formula used:
Increased % = 100 + increased
Decreased % = 100 - decreased
Calculations:
⇒ Mask manufactured in 2019 = X × (100 + 30) = X × 130%
⇒ Mask manufactured in 2020 = (130%X) × (100 + 15) = 115% (130% of X)
⇒ Mask manufactured in 2021 = 115% (130% of X) × (100 - 40) = 60% ( 115%( 130% of X))
But according to the question,
⇒ Manufactured in 2021 = 179400
So,
⇒ 60%{115%(130% of X)} = 179400
⇒ \(\frac{X × 60×115×130}{100×100×100}= 179400\)
⇒ X = \(\frac{179400 × 100×100×100}{60×130×115} \)
⇒ X = 200000
⇒ Hence, The manufacture of mask in 2018 is 200000
Shortcut Trick
So, 897 unit → 179400
then, 1000 unit → 179400/897 × 1000 = 200000