Grouping and Selections MCQ Quiz - Objective Question with Answer for Grouping and Selections - Download Free PDF

Given: Five friends Kapil, Ravi, Jatin, Hari, Shiva are working in a company.

Explanation:

Kapil, Shiva and Hari are intelligent.

Kapil, Ravi and Jitin are hard working.

Ravi, Hari and Jitin are honest.

According to above table, shiva is neither honest nor hardworking but is intelligent.

Hence, Option 1 is the correct answer.

Here, persons are K, L, M, N, O, P, Q and R; number of chocolates 5, 7, 9, 11, 12, 15, 16 and 18 and chocolates are Cadbury, Munch and Perk.

1) O bought Munch with only one other friend.

2) M and P bought different chocolates but not Munch.

3) Q and P bought same chocolate but not Cadbury.

4) L bought the chocolate which is the two digit prime number but different from P. Therefore, L has 11 chocolates.

5) R and O do not bought same type of chocolate.

6) K bought square number of chocolates but not the Perk. So, K has either 9 or 16.

7) The person who bought least number of chocolates purchases same chocolate as of L.

8) N bought one more chocolates than M but not Cadbury. Therefore, M has 15 chocolates and N has 16 chocolates and K has 9 chocolates.

9) R bought more chocolates than N but not the same type of chocolate. R has 18 chocolates.

10) Q bought more chocolates than only one person. Therefore, Q has 7 chocolates. By combining, all the conditions case 1, case 2, case 3 are eliminated. Hence, the final arrangement is as follows

Hence, O bought only 5 chocolates.

Here, persons are K, L, M, N, O, P, Q and R; number of chocolates 5, 7, 9, 11, 12, 15, 16 and 18 and chocolates are Cadbury, Munch and Perk.

1) O bought Munch with only one other friend.

2) M and P bought different chocolates but not Munch.

3) Q and P bought same chocolate but not Cadbury.

4) L bought the chocolate which is the two digit prime number but different from P. Therefore, L has 11 chocolates.

5) R and O do not bought same type of chocolate.

6) K bought square number of chocolates but not the Perk. So, K has either 9 or 16.

7) The person who bought least number of chocolates purchases same chocolate as of L.

8) N bought one more chocolates than M but not Cadbury. Therefore, M has 15 chocolates and N has 16 chocolates and K has 9 chocolates.

9) R bought more chocolates than N but not the same type of chocolate. R has 18 chocolates.

10) Q bought more chocolates than only one person. Therefore, Q has 7 chocolates. By combining, all the conditions case 1, case 2, case 3 are eliminated. Hence, the final arrangement is as follows

Hence, the correct combination is N - Perk.

Here, persons are K, L, M, N, O, P, Q and R; number of chocolates 5, 7, 9, 11, 12, 15, 16 and 18 and chocolates are Cadbury, Munch and Perk.

1) O bought Munch with only one other friend.

2) M and P bought different chocolates but not Munch.

3) Q and P bought same chocolate but not Cadbury.

4) L bought the chocolate which is the two digit prime number but different from P. Therefore, L has 11 chocolates.

5) R and O do not bought same type of chocolate.

6) K bought square number of chocolates but not the Perk. So, K has either 9 or 16.

7) The person who bought least number of chocolates purchases same chocolate as of L.

8) N bought one more chocolates than M but not Cadbury. Therefore, M has 15 chocolates and N has 16 chocolates and K has 9 chocolates.

9) R bought more chocolates than N but not the same type of chocolate. R has 18 chocolates.

10) Q bought more chocolates than only one person. Therefore, Q has 7 chocolates. By combining, all the conditions case 1, case 2, case 3 are eliminated. Hence, the final arrangement is as follows

Hence, the correct statement is L bought the same chocolate as of O who bought least number of chocolates. 

Here, persons are K, L, M, N, O, P, Q and R; number of chocolates 5, 7, 9, 11, 12, 15, 16 and 18 and chocolates are Cadbury, Munch and Perk.

1) O bought Munch with only one other friend.

2) M and P bought different chocolates but not Munch.

3) Q and P bought same chocolate but not Cadbury.

4) L bought the chocolate which is the two digit prime number but different from P. Therefore, L has 11 chocolates.

5) R and O do not bought same type of chocolate.

6) K bought square number of chocolates but not the Perk. So, K has either 9 or 16.

7) The person who bought least number of chocolates purchases same chocolate as of L.

8) N bought one more chocolates than M but not Cadbury. Therefore, M has 15 chocolates and N has 16 chocolates and K has 9 chocolates.

9) R bought more chocolates than N but not the same type of chocolate. R has 18 chocolates.

10) Q bought more chocolates than only one person. Therefore, Q has 7 chocolates. By combining, all the conditions case 1, case 2, case 3 are eliminated. Hence, the final arrangement is as follows

Since, both O and L bought same type of chocolates and L bought 11 chocolates which is the highest prime number as per given data.

Hence, the correct answer is One who bought highest prime number chocolates. 

Answer:- (3)

There are nine employees, A, B, C, D, E, F, G, H, and I.

Those are working in three different departments viz. IT, HR, and Production.

1. G works in the production department but not with D and H.

2. B works in the IT department but not with E and I.

4. Either D or C works along with B.

(No two persons with preceding or succeeding alphabetic series work in the same department.)

So, D works with B.

5. Neither E nor F works with G. 

6. A works in the HR department but not with C and F.

So, F works in the IT department.

7. Neither E nor F works with G.

8. A works in the HR department but not with C and F.

So, E works in the HR department and C works in the production department.

9. No two persons with preceding or succeeding alphabetic series work in the same department.

So, the final arrangement is,

Hence, employees C, G, I work in the Production department.

A team is to be selected from 13 players P1, P2, P3, P4, P5, P6, P7, P8, P9, P10, P11, P12 and P13.

1) P2 cannot be selected with P1, P6 or P4.

2) P7 cannot be selected with P2, P10, P11 or P13.

3) If P8 and P13 both are selected, then P5 must be selected.

4) P4 cannot be selected with P2, P10, PI2 or P11.

Option 1 - P1, P3, P4, P5, P6, P8, P9 in which P8 and P13 always with P5, So P13 not present with P8 and P5. So it is incorrect combination.

Option 2 - P1, P6, P11, P12, P13, P3, P4 in which P8 and P13 always with P5, so P5 and P8 not present and P4 cannot be selected with P11 and P12. So it is incorrect combination.

Option 3 - P1, P3, P4, P5, P8, P9, P13. follow all the condition. So it is correct combination. 

Option 4 - P2, P3, P5, P7, P8, P9, P13  in which P2 and P7 both together but in condition P2 and P7 never with same combination. So it is incorrect combination.

Hence, "option 3" is the correct answer.

Given,

• Two persons give one right answer and one wrong answer.
• Two persons give both answers wrong.

⇒ Thus, the day which is common in the answer of any two persons and also that day should not be answered by remaining two persons (who gave only wrong answers) would be the day today.

Tabulating the given information-

Thus, Wednesday is the common answer given by Person 1 and Person 4.

Also, Wednesday is not given as an answer by Person 2 and Person 3.

Thus, Wednesday is the day today.

Hence, 'option 4' is the correct answer.

According to the given information:

Given

Total students in a class = 120

Students participate in either Golf or Skating or both = 100

Total students participate in Golf = 60

Total students participate in Skating = 56

Concept used:

Used of Venn diagram.

From diagram,

Students who both play = 56 + 60 - 100 = 116 - 100 = 16

Now students who only Skating = 56 - 16 = 40

Hence, the correct answer is "40". 

Arranging them according to the given information,

Given,

B and C go in the first batch

B and H have to go together, so H is in the first batch

A and C never go together, so A is in the second batch

D and F do not go together

Case 1:

Case 2:

Among the given options A, D, E and G are in the second batch.

Given: Nine persons: J, K, L, M, N, O, P, Q and R 

Three departments: Marketing, Finance and HR

1. Only L work with M in the same department.

2. O works in the HR department.

3. R does not work in HR department. 

4. K who does not work with O and works in the Finance department. 

5. Q does not work with P but works with J. 

6. Only three people work in the HR department.

7. N and K work in two different departments. 

Hence, M does not work in the Finance department.

The combinations are:

Rahul + Kusum = Hindi + Maths------ (i )

Sameer + Rahul = Hindi + Biology-------(ii)

Gita + Kusum = Marathi + Maths-------(iii)

Sameer + Gita + Mihir = History + Biology-------(iv)

There can be two possible combinations for Marathi and Biology:

Using (ii) and (iii)

Sameer + Rahul = Hindi + Biology-------(ii)

Gita + Kusum = Marathi + Maths-------(iii)

But here no one is common so we cannot determine that person who is good in both Marathi and Biology.

Using (iii) and (iv)

Gita + Kusum = Marathi + Maths-------(iii)

Sameer + Gita + Mihir = History + Biology-------(iv)

Here Gita is common, so Gita is good in both Biology and Marathi.

Given:

Six persons: P, Q, R, S, U and T.

1. The one who read it last had taken it from R.

​

As R read the magazine before the Last one it means R read the magazine.

2. S was neither the first nor the last to read it.

As S was neither the first nor the last to read the magazine, S was read the magazine on the 2^nd or 3^rd , or 4^th number.so there are three cases.

3. S read it sometime before Q, who read it sometime after U

​There are 4 cases showing the reading number of 'Q' with respect to 'S'.

​

There are 7 cases showing the reading number of 'Q' with respect to 'U'.

4. There were as many readers between P and T as there were between R and P.

​So,​according to this statement, all the above 6 cases are eliminated only one case (case-2) remaining that shows the sequence of reading the magazine by all 6 persons.

As per the above statement, we can say that number of readers between P and T is equal to the number of readers between R and P. here Between T and P only one reader which is U. similarly, between P and R only one reader which is S.

Thus, T and Q have read the magazine first and last respectively.

Hence, The correct answer is "T and Q".                                                       

There are 9 people:  A, B, C, D, E, F, G, H and I

Three different cities: Mumbai, Kolkata, and Jaipur

1). A neither lives in Mumbai or Kolkata.

With this statement, We know A will live in Jaipur.

2). D and G are friends but live in different cities but none of them lives in Jaipur.

D and G will live in the same city but none of them lives in Jaipur means either they will live in Mumbai or Kolkata.

3). Either H or F lives in Kolkata.

4). B and G live in the same city but it's not Mumbai.

As we know G will live in Mumbai or Kolkata but with this statement, We know G will not live in Mumbai so she will live in Kolkata.

Here Case II eliminates as G will not live in Mumbai and case I Split into one more Case I.I

5). I, E and D are friends and the two of them live in the same city.

We already know that D lives in Mumbai so either E or I live in Mumbai.

6). E and H live in the same city but not Mumbai. 

Here, Case I.I eliminate as E does not live in Mumbai, E and H live in the same city, and there is no place in Kolkata.

So, E and H live in Jaipur.

As C is left so she will live in Mumbai and Since E lives in Jaipur so I will live in Mumbai.

So, The final arrangement is:

B, G and F live in Kolkata.

Mistake Points Kindly read the statement carefully, " I, E and D are friends and the two of them live in the same city." In solution, I and D both are living in the same city.

A cow has four legs and a hen has 2 legs.

Let the hens be y and the cows be x.

Given,

The number of legs are 14 more than twice the number of heads.

4x + 2y = 2(x + y) + 14

4x + 2y = 2x + 2y + 14

2x = 14

x = 7

So, number of cows are 7.