Classification of Crystalline Solids MCQ Quiz - Objective Question with Answer for Classification of Crystalline Solids - Download Free PDF

CONCEPT:

HCP Lattice and Tetrahedral Voids

• In a hexagonal close-packed (hcp) lattice, the number of atoms of the lattice (N) is proportional to the number of tetrahedral voids formed.
• Each atom in an hcp lattice creates two tetrahedral voids.
• If atoms of another element (M) occupy 1/3rd of the tetrahedral voids, we need to determine the ratio of M to N to find the formula of the compound.

EXPLANATION:

• Consider 1 unit cell of the hcp lattice, where the number of N atoms is 'n'.
• The number of tetrahedral voids formed will be 2n (since each N atom creates 2 tetrahedral voids).
• Given that M atoms occupy 1/3rd of the tetrahedral voids:
  • Number of M atoms = (1/3) * 2n = (2/3)n
• Thus, the ratio of M to N in the compound is (2/3)n : n or 2 : 3.

Therefore, the formula of the compound formed by elements M and N is M₂N₃.

The correct answer is Changes abruptly from solid to liquid when heated. Key Points

• Crystalline solids have a highly ordered and repeating atomic arrangement, which gives them their characteristic geometric shapes.
• They have a precise melting point, which is the temperature at which the ordered atomic arrangement breaks down and the solid transitions to a liquid state.
• The 3-dimensional layout of a crystalline solid is highly regular and symmetrical, with atoms or molecules arranged in a repeating pattern.
• When heated, a crystalline solid undergoes an abrupt phase transition from solid to liquid, without passing through an intermediate liquid crystal phase.

Additional Information

• Crystalline solids are resistant to geometric deformation due to their highly ordered atomic arrangement.
• Crystalline solids have a precise melting point, which is a characteristic feature of their structure.
• The layout of a crystalline solid is highly regular and symmetrical, with no unevenness in the arrangement of atoms or molecules.
• The key term 'crystalline solid' refers to a type of solid material with a highly ordered atomic structure, which gives it unique physical and chemical properties.

Concept : 

• Hexagonal close packing (HCP) is a type of crystal structure where atoms or ions are arranged in a close-packed pattern in three dimensions.
• In this arrangement, each atom has 12 nearest neighbors, with six arranged in a regular hexagonal pattern around it, and the other six forming an equilateral triangle above and below it.
• The HCP structure is one of the most efficient ways to pack spheres together, and it is found in many metallic and non-metallic elements

Explanation : 

In Hexagonal close packing (HCP) structure if the number of close packed spheres are N then the number of octahedral voids generated is N and the number of tetrahedral voids generated is 2N

Now, According to question, Atoms of element B form hcp lattice that means the number of atoms of element B will be 6 and thus, there will be 12 tetrahedral voids.

And as A occupy \(\frac{2}{3} \) of tetrahedral void.

Thus, Number of A = \(\frac{2}{3} \) × 12

Number of A= 8

Hence, the formula of the compound formed by the elements A and B is A₈B₆ which can be simplified to A4B3

Conclusion:

Therefore, the formula of the compound formed by the elements A and B is A4B3

The correct answer is Changes abruptly from solid to liquid when heated. Key Points

• Crystalline solids have a highly ordered and repeating atomic arrangement, which gives them their characteristic geometric shapes.
• They have a precise melting point, which is the temperature at which the ordered atomic arrangement breaks down and the solid transitions to a liquid state.
• The 3-dimensional layout of a crystalline solid is highly regular and symmetrical, with atoms or molecules arranged in a repeating pattern.
• When heated, a crystalline solid undergoes an abrupt phase transition from solid to liquid, without passing through an intermediate liquid crystal phase.

Additional Information

• Crystalline solids are resistant to geometric deformation due to their highly ordered atomic arrangement.
• Crystalline solids have a precise melting point, which is a characteristic feature of their structure.
• The layout of a crystalline solid is highly regular and symmetrical, with no unevenness in the arrangement of atoms or molecules.
• The key term 'crystalline solid' refers to a type of solid material with a highly ordered atomic structure, which gives it unique physical and chemical properties.

Concept : 

• Hexagonal close packing (HCP) is a type of crystal structure where atoms or ions are arranged in a close-packed pattern in three dimensions.
• In this arrangement, each atom has 12 nearest neighbors, with six arranged in a regular hexagonal pattern around it, and the other six forming an equilateral triangle above and below it.
• The HCP structure is one of the most efficient ways to pack spheres together, and it is found in many metallic and non-metallic elements

Explanation : 

In Hexagonal close packing (HCP) structure if the number of close packed spheres are N then the number of octahedral voids generated is N and the number of tetrahedral voids generated is 2N

Now, According to question, Atoms of element B form hcp lattice that means the number of atoms of element B will be 6 and thus, there will be 12 tetrahedral voids.

And as A occupy \(\frac{2}{3} \) of tetrahedral void.

Thus, Number of A = \(\frac{2}{3} \) × 12

Number of A= 8

Hence, the formula of the compound formed by the elements A and B is A₈B₆ which can be simplified to A4B3

Conclusion:

Therefore, the formula of the compound formed by the elements A and B is A4B3

The correct answer is Changes abruptly from solid to liquid when heated. Key Points

• Crystalline solids have a highly ordered and repeating atomic arrangement, which gives them their characteristic geometric shapes.
• They have a precise melting point, which is the temperature at which the ordered atomic arrangement breaks down and the solid transitions to a liquid state.
• The 3-dimensional layout of a crystalline solid is highly regular and symmetrical, with atoms or molecules arranged in a repeating pattern.
• When heated, a crystalline solid undergoes an abrupt phase transition from solid to liquid, without passing through an intermediate liquid crystal phase.

Additional Information

• Crystalline solids are resistant to geometric deformation due to their highly ordered atomic arrangement.
• Crystalline solids have a precise melting point, which is a characteristic feature of their structure.
• The layout of a crystalline solid is highly regular and symmetrical, with no unevenness in the arrangement of atoms or molecules.
• The key term 'crystalline solid' refers to a type of solid material with a highly ordered atomic structure, which gives it unique physical and chemical properties.

Concept : 

• Hexagonal close packing (HCP) is a type of crystal structure where atoms or ions are arranged in a close-packed pattern in three dimensions.
• In this arrangement, each atom has 12 nearest neighbors, with six arranged in a regular hexagonal pattern around it, and the other six forming an equilateral triangle above and below it.
• The HCP structure is one of the most efficient ways to pack spheres together, and it is found in many metallic and non-metallic elements

Explanation : 

In Hexagonal close packing (HCP) structure if the number of close packed spheres are N then the number of octahedral voids generated is N and the number of tetrahedral voids generated is 2N

Now, According to question, Atoms of element B form hcp lattice that means the number of atoms of element B will be 6 and thus, there will be 12 tetrahedral voids.

And as A occupy \(\frac{2}{3} \) of tetrahedral void.

Thus, Number of A = \(\frac{2}{3} \) × 12

Number of A= 8

Hence, the formula of the compound formed by the elements A and B is A₈B₆ which can be simplified to A4B3

Conclusion:

Therefore, the formula of the compound formed by the elements A and B is A4B3

CONCEPT:

HCP Lattice and Tetrahedral Voids

• In a hexagonal close-packed (hcp) lattice, the number of atoms of the lattice (N) is proportional to the number of tetrahedral voids formed.
• Each atom in an hcp lattice creates two tetrahedral voids.
• If atoms of another element (M) occupy 1/3rd of the tetrahedral voids, we need to determine the ratio of M to N to find the formula of the compound.

EXPLANATION:

• Consider 1 unit cell of the hcp lattice, where the number of N atoms is 'n'.
• The number of tetrahedral voids formed will be 2n (since each N atom creates 2 tetrahedral voids).
• Given that M atoms occupy 1/3rd of the tetrahedral voids:
  • Number of M atoms = (1/3) * 2n = (2/3)n
• Thus, the ratio of M to N in the compound is (2/3)n : n or 2 : 3.

Therefore, the formula of the compound formed by elements M and N is M₂N₃.

Concept : 

• Hexagonal close packing (HCP) is a type of crystal structure where atoms or ions are arranged in a close-packed pattern in three dimensions.
• In this arrangement, each atom has 12 nearest neighbors, with six arranged in a regular hexagonal pattern around it, and the other six forming an equilateral triangle above and below it.
• The HCP structure is one of the most efficient ways to pack spheres together, and it is found in many metallic and non-metallic elements

Explanation : 

In Hexagonal close packing (HCP) structure if the number of close packed spheres are N then the number of octahedral voids generated is N and the number of tetrahedral voids generated is 2N

Now, According to question, Atoms of element B form hcp lattice that means the number of atoms of element B will be 6 and thus, there will be 12 tetrahedral voids.

And as A occupy \(\frac{2}{3} \) of tetrahedral void.

Thus, Number of A = \(\frac{2}{3} \) × 12

Number of A= 8

Hence, the formula of the compound formed by the elements A and B is A₈B₆ which can be simplified to A4B3

Conclusion:

Therefore, the formula of the compound formed by the elements A and B is A4B3

Concept : 

• Hexagonal close packing (HCP) is a type of crystal structure where atoms or ions are arranged in a close-packed pattern in three dimensions.
• In this arrangement, each atom has 12 nearest neighbors, with six arranged in a regular hexagonal pattern around it, and the other six forming an equilateral triangle above and below it.
• The HCP structure is one of the most efficient ways to pack spheres together, and it is found in many metallic and non-metallic elements

Explanation : 

In Hexagonal close packing (HCP) structure if the number of close packed spheres are N then the number of octahedral voids generated is N and the number of tetrahedral voids generated is 2N

Now, According to question, Atoms of element B form hcp lattice that means the number of atoms of element B will be 6 and thus, there will be 12 tetrahedral voids.

And as A occupy \(\frac{2}{3} \) of tetrahedral void.

Thus, Number of A = \(\frac{2}{3} \) × 12

Number of A= 8

Hence, the formula of the compound formed by the elements A and B is A₈B₆ which can be simplified to A4B3

Conclusion:

Therefore, the formula of the compound formed by the elements A and B is A4B3

Concept : 

• Hexagonal close packing (HCP) is a type of crystal structure where atoms or ions are arranged in a close-packed pattern in three dimensions.
• In this arrangement, each atom has 12 nearest neighbors, with six arranged in a regular hexagonal pattern around it, and the other six forming an equilateral triangle above and below it.
• The HCP structure is one of the most efficient ways to pack spheres together, and it is found in many metallic and non-metallic elements

Explanation : 

In Hexagonal close packing (HCP) structure if the number of close packed spheres are N then the number of octahedral voids generated is N and the number of tetrahedral voids generated is 2N

Now, According to question, Atoms of element B form hcp lattice that means the number of atoms of element B will be 6 and thus, there will be 12 tetrahedral voids.

And as A occupy \(\frac{2}{3} \) of tetrahedral void.

Thus, Number of A = \(\frac{2}{3} \) × 12

Number of A= 8

Hence, the formula of the compound formed by the elements A and B is A₈B₆ which can be simplified to A4B3

Conclusion:

Therefore, the formula of the compound formed by the elements A and B is A4B3