Question
Download Solution PDFX's 16th birthday is on 9th March which falls on Sunday of a leap year. What will be the day on his 20th birthday?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven: X's 16th birthday is on 9th March which falls on Sunday of a leap year.
As leap year is every 4 years, therefore 20th birthday will in the next subsequent leap year.
So, number of odd days from 16th birthday to 20th birthday → 2 ( 2 Ordinary years) + 2 (1 Leap year) ⇒ 4
Thus, X's 20th March falls on → Sunday + 4 → Friday
Hence, "Option 2" is the correct answer.
Additional Information
No. of odd days | Ordinary year | Leap year |
365 ÷ 7 = 52 weeks + 1 odd day |
366 ÷ 7 = 52 weeks + 2 odd day |
Years | No. of odd days |
100 | 5 |
200 | 3 |
300 | 1 |
400 | 0 |
Note : Multiple of 400 years i.e 800, 1200, 1600, 2000 will also have 0 odds days.
Days | No. of odd days |
Sunday | 0 |
Monday | 1 |
Tuesday | 2 |
Wednesday | 3 |
Thursday | 4 |
Friday | 5 |
Saturday | 6 |
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