Question
Download Solution PDFWhich of the following is not the Maxwell's equation?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The equation that relate partial derivatives of properties of p, v, T and s of a compressible fluid are called Maxwell relations.
The four Gibbsian relations for a unit mass are
1) du = Tds – Pdv
2) dh = Tds + vdP
3) df = - Pdv – sdT
4) dg = -sdT + vdP
Since u,h,f and g are the properties thus point functions and the above relations can be expressed as
dz = Mdx + Ndy
with,
\({\left( {\frac{{\partial T}}{{\partial v}}} \right)_s} = \; + {\left( {\frac{{\partial p}}{{\partial s}}} \right)_v}\)
Applying the cyclic relation as
Mdx + Ndy → \({\left( {\frac{{\delta M}}{{\delta y}}} \right)_x} = {\left( {\frac{{\delta N}}{{\delta x}}} \right)_y}\)
Now,
Replacing M,N,y and x by T,p,v,s of each of the Gibbsian equations in cyclic order, we will get the following four relations.
\(1){\left( {\frac{{\partial T}}{{\partial p}}} \right)_s} = {\left( {\frac{{\partial v}}{{\partial s}}} \right)_p}\;\)
\(2){\left( {\frac{{\partial p}}{{\partial T}}} \right)_v} = {\left( {\frac{{\partial s}}{{\partial v}}} \right)_T}\;\)
\(3){\left( {\frac{{\partial T}}{{\partial v}}} \right)_s} = - {\left( {\frac{{\partial p}}{{\partial s}}} \right)_v}\)
\(4){\left( {\frac{{\partial v}}{{\partial T}}} \right)_p} = - {\left( {\frac{{\partial s}}{{\partial p}}} \right)_T}\)
Last updated on Jul 15, 2025
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