Question
Download Solution PDFWhat is the oxidation state of Vanadium in V2O5?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is +5.
Key Points
- The oxidation state of an element is the charge it would have if all bonds were ionic.
- In V2O5, oxygen typically has an oxidation state of -2.
- Since there are 5 oxygen atoms, their total oxidation state is 5 x -2 = -10.
- To balance this, the total oxidation state of the two vanadium atoms must be +10.
- Therefore, the oxidation state of each vanadium atom is +10 / 2 = +5.
Additional Information
- Oxidation States
- Oxidation states are used to keep track of electrons in atoms.
- They are especially useful in redox reactions where electrons are transferred between species.
- Vanadium
- Vanadium can exhibit multiple oxidation states, commonly +2, +3, +4, and +5.
- It is often used in industries for producing strong alloys.
- Vanadium Pentoxide (V2O5)
- Vanadium pentoxide is a compound where vanadium is in the +5 oxidation state.
- It is used as a catalyst in the production of sulfuric acid and in the ceramics industry.
Last updated on Jul 8, 2025
->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.
->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.