What is the escape speed on earth for any object?

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  1. 11.2 m/s
  2. 11.2 km/h
  3. 11.2 km/s
  4. None of these

Answer (Detailed Solution Below)

Option 3 : 11.2 km/s
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HP JBT TET 2021 Official Paper
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Detailed Solution

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Concept:

Escape Velocity (v): 

  • The minimum velocity required to escape the gravity of the earth is called escape velocity.
  • If an object is through with this speed or above, it will escape the gravity of earth and will not return back. 
  • Escape velocity (ve) for a body on earth is given as 
  • \(V_e = \sqrt {\frac{2GM}{R}}\)

    G is the universal gravitational constant, M is the mass of earth, R is the radius of the earth.

​Explanation:

The value of the Universal gravitational constant is G = 6.67 × 10-11 N kg-2 m2.

Mass of Earth is  M = 5.972 × 1024 kg

Radius of earth is R = 6370000 m

Putting this in the expression of escape velocity we will get the value of it around 11.2 km/s. 

So the correct option is 11.2 km/s

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