Two coils A and B are arranged parallel to each other. When the current in coil B increases at the rate of 20 A/s and initial current in coil A is zero, the induced emf in coil A is 100 V. The mutual inductance of the two coil is:

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  1. 6 H
  2. 4 H
  3. 7 H
  4. 5 H

Answer (Detailed Solution Below)

Option 4 : 5 H
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Detailed Solution

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Concept:

  • When two coils are brought in proximity to each other the magnetic field in one of the coils tends to link with the other.
  • This further leads to the generation of voltage in the second coil.
  • This property of a coil that affects or changes the current and voltage in a secondary coil is called mutual inductance.

F1 Madhuri Defence 20.12.2022 D1

  • The emf induced in the coil is given as, \(e = -M\frac{dI}{dt}\) where M = mutual inductance,  e = emf induced in the coil, i = current

Calculation:

Given,

The current in coil B increases at the rate, \(\frac{dI_B}{dt}=20 A/s\)

The initial current in coil A, IA = 0A

The induced emf in a coil A, eA = 100 V

The mutual inductance of the two coils is calculated as, \(e=-M\frac{di}{dt} \)

\(e_A=-M\frac{d(I_A-I_B)}{dt}\)

\(e_A=-M(\frac{dI_A}{dt}-\frac{dI_B}{dt})\)

\(100=-M(0-20)\)

\(M=\frac{100}{20}=5 H\)

Hence, the mutual inductance of the two coils is 5 H.

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