Theoretical velocity of jet of water from orifice is given by

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Question

This question was previously asked in

JKSSB JE Civil Jal Shakti 6 Dec 2022 Official Paper (Shift 1)

Answer 1

Explanation:

F2 M.J Madhu 26.05.20 D2

Taking datum through the axis of the orifice and applying Bernoulli’s equation to points 1 and 2,
\(\frac{P_{1}}{\gamma}+\frac{V_{1}^2}{2g}+H=\frac{P_{2}}{\gamma}+\frac{V_{2}^2}{2g}+0 \) , As the pressure at points 1 and 2 is atmospheric, p₁ = p₂= 0. Further, if the cross-sectional area of the tank is very large, the liquid at point 1 is practically standstill and hence V₁= 0.

∴ Theoretical velocity of jet of water from the orifice is

\(\frac{V_{2}^2}{2g} = H \,\,\,\,\Rightarrow \,\,\,V_{2} = \sqrt {2gH} \)