The value of transmission parameter A for the two-port network shown is

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  1. Zero
  2. 0.5
  3. 2
  4. 1

Answer (Detailed Solution Below)

Option 4 : 1

Detailed Solution

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Concept: 

ABCD Parameter defines for two-port network

\(\left[ {\begin{array}{*{20}{c}} {{{\rm{V}}_{\rm{1}}}}\\ {{{\rm{I}}_{\rm{1}}}} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} {\rm{A}}&{\rm{B}}\\ {\rm{C}}&{\rm{D}} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{{\rm{V}}_{\rm{2}}}}\\ {{{\rm{I}}_{\rm{2}}}} \end{array}} \right]\)

V1 = A V2 + B I2

I1 = C V2 + D V2

V1 = Input voltage 

V2 = Output voltage

I1 = Input current

I2 = Output current

A, B, C, D = T-parameter

Calculation:

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according to the diagram 

V1 = A V2 + B I2

V1 = -5I2 + V2

Compare both equations

A = 1

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